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weqwewe [10]
3 years ago
7

Identify the properties used for the first two steps in simplifying 6ab2 + 4a2b – 3ab2 + 3a2b – 2a2b2.

Mathematics
2 answers:
podryga [215]3 years ago
5 0

Answer:

<u>commutative property of addition </u>

<u>distributive property</u>

Step-by-step explanation:

Identify the properties used for the first two steps in simplifying 6ab2 + 4a2b – 3ab2 + 3a2b – 2a2b2.

6ab2+4a2b-3ab2+3a2b-2a2b2 = 4a2b+3a2b-3ab2+6ab2-2a2b2 -<u>commutative property of addition</u>

= (4+3)a2b+(-3+6)ab2-2a2b2  

 = 7a2b+3ab2-2a2b2 -<u>distributive property</u>

Kryger [21]3 years ago
3 0
The expression 6ab^2+4a^2b-3ab^2+3a^2b-2a^2b^2 has two similar pairs of <span>conjunctions.
</span>
1. Rewrite this expression as
6ab^2+4a^2b-3ab^2+3a^2b-2a^2b^2=
=(6ab^2-3ab^2)+(4a^2b+3a^2b)-2a^2b^2
and then 
2. add the similar <span>conjunctions
</span><span>
</span><span>(6ab^2-3ab^2)+(4a^2b+3a^2b)-2a^2b^2=3ab^2+7a^2b-2a^2b^2.</span><span>
</span><span />

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3 years ago
Match each question to the correct problem.
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<h2>Answer:</h2>

<em>(Check attached images).</em>

<h2>Step-by-step explanation:</h2>

<h3>Exercise 1.</h3>

a. Convert to decimals.

To order the numbers from least to greaters, convert them to decimals and compare.

5.2(percent)=0.052\\ \\\frac{1}{7} =0.1429\\\\ -0.8=-0.8000\\ \\\frac{-11}{5} =-2.2

b. Select the second least number.

-0.8.

<h3>Exercise 2.</h3>

a. Convert to decimals.

-3.4(percent)=-0.034\\ \\-0.031\\\\ -0.2\\ \\-\sqrt{0.8}= -0.8944

b. Select the correct number.

-\frac{1}{5}.

<h3>Exercise 3.</h3>

a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the positive numbers.</em>

<em>59%=0.59</em>

<em>3/5=0.6</em>

<em />

b. Select the correct number.

3/5.

<h3>Exercise 4.</h3>

a. Convert to decimals.

-0.35

-3.5%= -0.035

b. Conclude.

Seeing that -3.5% is less than -0.35, the symbol that makes the statement true is ">".

<h3>Exercise 5.</h3>

a. Try to visually estimate b.

B appears to have a value of -0.9.

b. Convert the numbers to decimals.

-3.4%= -0.034

-0.031

-1/5= -0.2

-\sqrt{0.8}= -0.8944

c. Select the correct answer.

<em>Since we estimated the value of b as -0.9, the number that best adequates to its value is </em>-\sqrt{0.8}.

<h3>Exercise 6.</h3>

a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the positive numbers.</em>

5.2%= 0.052

1/7= 0.1429

b. Select the correct number.

5.2% is the second largest.

<h3>Exercise 7.</h3>

a. Convert to decimals.

6/7= 0.857143

0.857

b. Select the correct answer.

Seeing that 0.857 is marked as an approximate by the

ellipsis,  and considering that 6/7 is an irrational numbers, we can conclude that the number that better fits the situation and makes the statement true is "=".

<h3>Exercise 8.</h3>

a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the negative numbers.</em>

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3. The measures of the angles of a triangle are in the extended ratio 2:3. 10. What is the measure of the
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Step-by-step explanation:

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Answer:

P( 31 < \bar X< 41)

And we can ue the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got for the limits:

z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515

z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

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\mu=37 and \sigma=28  and we are omitting the zeros from the thousand to simplify calculations

We select a sample size of n=50>30.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P( 31 < \bar X< 41)

And we can ue the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got for the limits:

z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515

z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01

So we want to find this probability:

P(-1.515

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Answer:

Step-by-step explanation:

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