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2 years ago

Explain why there must be at least two lines on any given plane

Mathematics

1 answer:

Svetach [21]2 years ago

7 0

There has to be at least two lines on any given plane in order to plot an order pair.

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The diameter of a circle is 7 ft. Find its area to the nearest tenth.

Mumz [18]

Answer:

38.5ft²

Step-by-step explanation:

we know the formula for Area is

A=pi*r²

A=38.5

6 0

2 years ago

Can someone please help me?:\

katrin [286]

The circumference of the top of the cake is $9.5\pi\approx29.845$ in.

It sounds like the baker is trying to line the circumference with cherriesto fit as many as possible along the border, like in the picture I've attached below.

This comes down to dividing the cake's circumference by the diameter of each cherry:

$\dfrac{9.5\pi}{0.75}\approx39.79$

or about 39 cherries, making the answer D.

7 0

2 years ago

(9q r+6qr +20g)+(-6qr -qr -11q-4q r)=

Arte-miy333 [17]

4qr+20g-11q hopefully this would help you

6 0

3 years ago

11) It's perimeter

natta225 [31]

2.8 m = .0028 km
3.5/.0028 = 1259 revolutions

8 0

2 years ago

A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 27 mi/hr. Another ship leaves the same port at 1:30 P.M. and tr

Len [333]

To solve this problem you must apply the proccedure shown below:

1. You must apply the Law of Cosines, as you can see in the figure attached. Then:

- The first ship travels at $27 mi/hr$ in for two hours. Therefore, the side $a$ is:

$a=(27 mi/hr)(2 hr)=54mi$

- The second ship travels at $18 mi/hr$ for $1.5 hours$ . Therefore, the side $b$ is:

$b=(18mi/hr)(1.5hr)=27mi$

- Now, you can calculate $c$ :

$c=\sqrt{54^{2}+27^{2}-2(54)(27)Cos(55)}=44 mi$

The answer is: $44 miles$

8 0

2 years ago