WORTH 25 HELP ASAP!!!
1 answer:
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Answer:
The 20 quarts are used for 6% butterfat milk and 10 quarts are used for 3% butterfat milk .
Step-by-step explanation:
As given
6% butterfat milk and 3% butterfat milk should be mixed to yield 30 quarts of 5% butterfat milk .
Let us assume that x quarts are used for 6% butterfat milk .
Than (30 - x) quarts are used for 3% butterfat milk .
6% is written in the decimal form
= 0.06
3% is written in the decimal form
= 0.03
5% is written in the decimal form
= 0.05
Than the equation becomes
0.06 × x + (30 - x) × 0.03 = 30 × 0.05
0.06x + 0.9 - 0.03x = 1.5
0.06x - 0.03x = 1.5 - 0.9
0.03x = 0.6
x = 20 quarts for 6% butterfat milk .
(30 - x ) = (30 - 20) = 10 quarts for 3% butterfat milk .
Than 20 quarts are used for 6% butterfat milk and 10 quarts are used for 3% butterfat milk .
Answer:
we reject H₀
Step-by-step explanation: Se annex
The test is one tail-test (greater than)
Using α = 0,05 (critical value ) from z- table we get
z(c) = 1,64
And Test hypothesis is:
H₀ Null hypothesis μ = μ₀
Hₐ Alternate hypothesis μ > μ₀
Which we need to compare with z(s) = 2,19 (from problem statement)
The annex shows z(c), z(s), rejection and acceptance regions, and as we can see z(s) > z(c) and it is in the rejection region
So base on our drawing we will reject H₀
