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sesenic [268]
2 years ago
6

WORTH 25 HELP ASAP!!!

Mathematics
1 answer:
Paul [167]2 years ago
3 0
I put in the x coordinate for where y was 80 and the y coordinate for where x was 3. Then I subtracted them to get the slope. Hope this helps.

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Find the slope of the line through the points (4, 8) and (5, 10).
Ulleksa [173]

Answer:

the slope is 2. or m=2

Step-by-step explanation:

basically

\frac{10-8}{5-4} =\frac{2}{1} =2

7 0
2 years ago
HELL PICTURE SHOWN!!!
Arturiano [62]
I believe it is A
Don't be mad at me if I get it wrong.
:-)
8 0
3 years ago
Read 2 more answers
8. What is the domain of <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Bx%5E%7B2%7D%20%2B20x%2B75%7D" id="TexFormula1" title
antiseptic1488 [7]

Answer:

8.  Domain: (-∞, -15) ∪ (-15, -5) ∪ (-5, ∞)

9.  Domain: [7/13, ∞)

    Range: [1, ∞)

Step-by-step explanation:

<u>Question 8</u>

Given rational function:

f(x)=\dfrac{x}{x^2+20x+75}

Factor the denominator of the given rational function:

\implies x^2+20x+75

\implies x^2+5x+15x+75

\implies x(x+5)+15(x+5)

\implies (x+15)(x+5)

Therefore:

f(x)=\dfrac{x}{(x+15)(x+5)}

<u>Asymptote</u>: a line that the curve gets infinitely close to, but never touches.

The function is <u>undefined</u> when the <u>denominator equals zero</u>:

x+15=0 \implies x=-15

x+5=0 \implies x=-5

Therefore, there are <u>vertical asymptotes</u> at x = -15 and x = -5.

<u>Domain</u>: set of all possible input values (x-values)

Therefore, the <u>domain of the given rational function</u> is:

(-∞, -15) ∪ (-15, -5) ∪ (-5, ∞)

---------------------------------------------------------------------------------

<u>Question 9</u>

Given function:

f(x)=\sqrt{13x-7}+1

<u>Domain</u>: set of all possible input values (x-values)

As the <u>square root of a negative number</u> is <u>undefined</u>:

\implies 13x-7\geq 0

\implies 13x\geq 7

\implies x\geq \dfrac{7}{13}

Therefore, the <u>domain of the given function</u> is:

\left[\dfrac{7}{13},\infty\right)

<u>Range</u>: set of all possible output values (y-values)

\textsf{As }\:\sqrt{13x-7}\geq 0

\implies \sqrt{13x-7}+1\geq 1

Therefore, the <u>range of the given function</u> is:

[1, ∞)

8 0
1 year ago
What is the range of function g if g (x) = f(x) + 3?
masya89 [10]
I think it is D, hope it helps
7 0
2 years ago
What measure describe a isosceles triangle
Shkiper50 [21]

it has 2 equal sides and 1 unequal side


5 0
3 years ago
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