Question

The function g(x) is defined as g(x) = 6x2 + 23x – 4. When does g(x) = 0?

Answer 1

6x^2 + 23x  - 4 = 0
factorising:-

(6x - 1)(x  + 4 ) = 0

x = 1/6 , - 4

Answer 2

Answer:

x=1/6 and x=-4 are the zeroes of the given equation.

Hence, at these points we will get g(x)=0

Step-by-step explanation:

We have been given the function:

$g(x)=6x^2+23x-4$

When g(x)=0 we will put g(x)=0 we get:

$6x^2+23x-4=0$

We will factorize the above equation:

$6x^2+24x-x-4=0$

$6x(x+4)-1(x+4)=0$

$(6x-1)(x+4)=0$

Now we will equate both the factors to zero we get:

(6x-1)=0 and (x+4)=0

x=1/6 and x=-4 are the zeroes of the given equation.

Hence, at these points we will get g(x)=0