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4 years ago

What is (3x+5)(x^2+6x+11)

Mathematics

1 answer:

serg [7]4 years ago

3 0

Answer:

$\large\boxed{3x^3+23x^2+63x+55}$

Step-by-step explanation:

$\text{Use FOIL:}\\\\(a+b)(c+d)=ac+ad+bc+bd$

$(3x+5)(x^2+6x+11)\\\\=(3x)(x^2)+(3x)(6x)+(3x)(11)+(5)(x^2)+(5)(6x)+(5)(11)\\\\=3x^3+18x^2+33x+5x^2+30x+55\qquad\text{combine like terms}\\\\=3x^3+(18x^2+5x^3)+(33x+30x)+55\\\\=3x^3+23x^2+63x+55$

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HELPPPP will be appreciated PLEASEEEE

iren2701 [21]

Cos(r)=10/26
cos(s)=24/26
sin(r)=24/26
sin(s)=10/26
tan(r)=24/10
tan(s)=10/24
I hope these are right :)

7 0

3 years ago

Increase or decrease 32 pages to 28 Pages round to the nearest tenth of a percent

Amiraneli [1.4K]

Hello! I would love to help!

Let's start by decreasing 32 pages to 28. How many pages does it take to get from 28 to 32? Let's subtract to find out!

32-28=4

Okay, now we know 28 pages is 4 less than 32.

Now, what percentage did it decrease by? Let's find out by dividing!

4/32=0.125

Let's make that decimal into a percentage by multiplying it by 100.

0.125*100=12.5

So, we now know the answer is...

decreased by 12.5%

Hope this helped! Comment if you have questions!

6 0

3 years ago

I need help asap!! Will mark the brainliest of correct!

Anettt [7]

Answer:

15.81

Step-by-step explanation:

7 0

3 years ago

How do I show that |3 + 10| = |3| + |10|

forsale [732]

Because the absolute value of both is 13. Just put 13=13

4 0

3 years ago

What is cos theta when sin theta = sqrt 2/3

Fittoniya [83]

Answer:

Value of cosθ is ±√7/3 .

Step-by-step explanation:

According to the Question , value of :

$\red{\implies sin\theta = \dfrac{\sqrt2}{3}}$

And , we know the identity of sine and cosine as ,

$\boxed{\pink{\sf\implies sin^2\theta + cos^2\theta = 1} }$

Using , this identity we have ;

$\implies sin^2\theta + cos^2\theta = 1 \\\\\implies \bigg( \dfrac{\sqrt2}{3}\bigg)^2 + cos^2\theta = 1 \\\\\implies \dfrac{2}{9} + cos^2\theta = 1 \\\\\implies cos^2\theta = 1 - \dfrac{2}{9} \\\\\implies cos^2\theta = \dfrac{9-2}{9} \\\\\implies cos\theta = \sqrt{\dfrac{7}{9}} \\\\\underline{\boxed{\blue{\bf \implies cos\theta = \pm \dfrac{\sqrt 7 }{3}}}}$

Now , here since θ is in 2nd quadrant and in 2nd quadrant cos is negative . Hence ,the value of cos will be :

$\boxed{\orange{\bf \implies cos\theta =-\dfrac{\sqrt7}{3}}}$

3 0

3 years ago