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3 years ago

Is 5,000 cm greater than 5 m

2 answers:

8 0

Yes, because 100cm = 1meter so divide the 5,000cm by 100 and 5,000 cm is 50 m . In order to compare the measurements they have to have the same units

ANTONII [103]3 years ago

3 0

That is false 5,000cm is bigger you got this way to go

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Find the sum of each series, if it exists<br>91 + 85 + 79 + … + (29)

Natali [406]

Answer:

651.

Step-by-step explanation:

Note: In the given series it should be -29 instead of 29 because 29 cannot be a term of AP whose first term is 91 and common difference is -6.

Consider the given series is

$91+85+79+...+(-29)$

It is the sum of an AP. Here,

First term = 91

Common difference = 85 - 91 = -6

Last term = -29

nth term of an AP is

$a_n=a+(n-1)d$

where, a is first term and d is common difference.

$-29=91+(n-1)(-6)$

$-29-91=(n-1)(-6)$

$\dfrac{-120}{-6}=(n-1)$

$20=(n-1)$

$n=20+1=21$

Sum of AP is

$Sum=\dfrac{n}{2}[\text{First term + Last term}]$

$Sum=\dfrac{21}{2}[91+(-29)]$

$Sum=\dfrac{21}{2}[62]$

$Sum=651$

Therefore, the sum of given series is 651.

5 0

2 years ago

Which of the following expressions is equivalent to 4^-3?<br><br>

-BARSIC- [3]

Answer:

x(12y+4)

Step-by-step explanation:

6 0

2 years ago

Need 24 26 28 and 30 dne, first correct will get brainiest

Galina-37 [17]

Answer:

Many answers, look below :)

Step-by-step explanation:

24.

(x)=2x^5+6x^4

3 0

3 years ago

Find measures of each exterior angle of a regular polygon with 16 sides

Maksim231197 [3]

The measure of each exterior angle = the measure of each central angle.
each angle = 360 / 16 = 22.5

3 0

3 years ago

Read 2 more answers

There are 5 very different seats in a car. In how many ways can 5 different people be seated in the car for a road trip if only

avanturin [10]

Answer:

Step-by-step explanation:

Let A and B be the two people who are able to drive. If A is driving, there are 4! ways to arrange the remaining peoplein the car seats. If B is driving, there are also 4! ways to arrange the remaining people. The number of arrangements 'n' is:

$n=2*4!\\n=2*4*3*2*1\\n=48\ ways$

They can be arranged in 48 ways.

6 0

3 years ago