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dezoksy [38]
3 years ago
9

Help with number 9 plz

Mathematics
1 answer:
IrinaVladis [17]3 years ago
4 0
The answer is C. 16,200 cubic feet.

Hope I helped !!!

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The factorization of 8x3 – 125 is (2x – 5)(jx2 + kx + 25). What are the values of j and k
Inga [223]

Answer:

j=4\\k=10

Step-by-step explanation:

8x^3 - 125

\left(2x\right)^3-5^3

Use this formula:

x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)

Where,

x=2x\\y=5

Substitute in the values.

\left(2x\right)^3-5^3=\left(2x-5\right)\left(2^2x^2+5\cdot \:2x+5^2\right)

\left(2x-5\right)\left(4x^2+10x+25\right)

4 0
3 years ago
Find S10 for -1 + -7 + -13 + -19
Alex777 [14]
First we find the common difference...to do this we subtract the first term from the second term. -7 - (-1) = -7 + 1 = -6

now we are going to find the 10th term
an = a1 + (n-1)*d <== formula for finding any term in arithmetic series
a1 = 1st term, d = common difference, n = term we want to find
now we sub
a10 = -1 + (10 -1) * -6
a10 = -1 + (9 * -6)
a10 = -1 - 54 
a10 = - 55

now we will find the sum
Sn = (n (a1+ an)) / 2 <== formula for finding the sum 
S10 = (10(-1 - 55))/2
S10 = (10(-56) / 2
S10 = -560/2
S10 = - 280

so the sum of the first 10 numbers is -280

4 0
3 years ago
How many books recommended by the book reading club would you actually buy? Which book was first recommended to be read by the b
avanturin [10]

Answer:

7

Step-by-step explanation:

njshhtb jahhhdvjsjjbvgshh shhkakhgsv jjjjgfe

4 0
2 years ago
The angles in a triangle are in the ratio 1:2:3 a) Show that the triangle is a right -angled triangle b) The hypotenuse of the t
Hitman42 [59]

Answer:

8.5 cm

Step-by-step explanation:

Angles of the triangle:

  • x+2x+3x= 180
  • 6x= 180
  • x= 30
  • 30°, 60° and 90°

Right triangle as it has 90° angle

Sides are a, b and 19 cm

  • sin 30°= a/19 ⇒ a= 19 sin 30°= 19*0.5= 8.5 cm  = shortest side
  • sin 60°= b/19 ⇒ b= 19 sin 60°= 19*0.866= 16.45 cm
5 0
3 years ago
Which expression is equivalent to a^m divide a^n?(20points)
Citrus2011 [14]
<h3><u>Answer</u> :</h3>

\bigstar\:\boxed{\bf{\dfrac{a^m}{a^n}=a^{m-n}}}

<h3><u>Learn More</u> :</h3>

\dag\sf\:\:a^m\times a^n=a^{m+n}

\dag\sf\:\:\dfrac{a^m}{a^n}=a^{m-n}=\dfrac{1}{a^{n-m}}

\dag\sf\:\:a^{-m}=\dfrac{1}{a^m}

\dag\sf\:\:(a^{m})^n=a^{mn}

\dag\sf\:\:a^1=a

\dag\sf\:\:a^0=1

\dag\sf\:\:\sqrt[n]{a^m}=a^{\frac{m}{n}}

6 0
3 years ago
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