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Vladimir79 [104]
3 years ago
12

What is the coefficient of the second term of the trinomial? (4a+5)2=16a2+Ba+25 Enter your answer in the box. B =

Mathematics
1 answer:
DochEvi [55]3 years ago
3 0

Answer:

B=40

Step-by-step explanation:

we know that

(a+b)^{2}=a^{2}+2ab+b^{2}

In this problem we have

(4a+5)^{2}=16a^{2}+Ba+25

The second term of the trinomial is equal to

2(4a)(5)=40a

therefore

B=40

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3 0
3 years ago
a rectangular lawn has an area of a^3 - 125. use the difference of cubes to find out the dimensions of the rectangle.
ANEK [815]

The area of a rectangle is the product of its dimensions

The dimensions of the rectangle are: \mathbf{Length = a -5} and \mathbf{Width = a^2 + 5a + 25}

The area is given as:

\mathbf{Area = a^3 - 125}

Express 125 as 5^3

\mathbf{Area = a^3 - 5^3}

Apply difference of cubes

\mathbf{Area = (a - 5)(a^2 + 5a + 5^2)}

\mathbf{Area = (a - 5)(a^2 + 5a + 25)}

The area of a rectangle is:

\mathbf{Area = Length \times Width}

So, by comparison:

\mathbf{Length = a -5}

\mathbf{Width = a^2 + 5a + 25}

Read more about areas at:

brainly.com/question/3518080

6 0
2 years ago
I need help with this question i dont understand it
RUDIKE [14]
The perimeter, by definition, is the outside measure of that figure. MN and LM are the same length and LK and NK are the same length....we just need to find the lengths! Use the distance formula to find the distance between the 2 points:
\sqrt{( x_{2} - x_{1} ) ^{2} +( y_{2}- y_{1} ) ^{2}  }
For the segment MN, use the coordinates of M as your x1, y1, and use the coordinates of N for x2, y2:
\sqrt{(3-2) ^{2}+(4-3) ^{2}  }
which simplifies to
\sqrt{(1 )^{2}+(1) ^{2}  } which is \sqrt{2}
So that is the length of both MN and LM.  So far our perimeter is \sqrt{2} + \sqrt{2}=2 \sqrt{2}
Now let's use the same formula to find out the length of one of the longer segments:
\sqrt{(5-3) ^{2} +(3-2) ^{2} }
which simplifies down to
\sqrt{(2) ^{2} +(1) ^{2} }
which is of course \sqrt{5}
Since we have 2 of those lengths, \sqrt{5} + \sqrt{5}=2 \sqrt{5}
So our perimeter is, in the end, 2 \sqrt{2}+2 \sqrt{5}
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3 years ago
In the diagram find the area of DEF
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Answer:

Im sorry Im not sure

Step-by-step explanation:

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