We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d
we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor
p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)
therefor
p=d(x+4) and
x^2-5x+6=d(x-2)
we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub
p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
Answer:
ΔABD ≅ ΔACD by SAS, therefore;
by CPCTC
Step-by-step explanation:
The two column proof is presented as follows;
Statement
Reason
ABCD is a trapezoid
Given
Given
Definition of a trapezoid
ABCD is an isosceles trapezoid
Left and right leg are equal
∠BAD ≅ ∠CDA
Base angle of an isosceles trapezoid are congruent
Reflexive property
ΔABD ≅ ΔACD
By SAS rule of congruency
CPCTC
CPCTC; Congruent Parts of Congruent Triangles are Congruent
SAS; Side Angle Side rule of congruency
I hope you know what '!' means
2!=2
3!=6
4!=24
basicalkly times every natural number including and before that number
nCr=

so

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First, we draw our line.
|------------------------------------------------------------------------------------|
a e
Next, break up this line into segments using the information.
|----------------------|----------------------|--------------------|------------------|
a b c d e
The entire line is 29.
ab + bc + cd + de = ae
ab + bc + cd + de = 29
You also know that
bd = bc + cd
Due to midpoint theorem,
ab = bc
cd = de
Then,
2ab + 2cd = 29
The equations we will use are
bd = bc + cd eq1
2bc + 2cd = 29 eq2
Dividing both sides of the equation in eq2 yields
bc + cd = 14.5
bd = bc + cd
bd = 14.5