Think about this as a table of values where domain is the x values and range is the y values.
f(4) wants the y-value when the x-value is 4
f(4) = 1/2
The second question wants us to find the x-value when f(x) also known as the y-value is 4.
f(x) = 4
x = 8
answers: 1/2, 8
Ok so you have 4, x^6 / 2, x^4. Now divide the coefficient so 4/2=2. So 2 x^6/x^4, now subtract the numerator by the denominator so x^6-x^4=x^2 so now you have 2x^2
Answer: 2x^2
Uh oh speggego's im telling teacher lol
144, 4:6 simplifies to 2:3, if you divide 96 by 2 you get 48, and 48 x 3 = 144
Answer:
A. AAS
Step-by-step explanation:
