yes, there are infinitety many polynomial that have exactly one real root just like your example, to determine the real root first let the real root is a, and the complex roots are b±ic the polynomial satisfy
-9x³ + 19x² + 17 = -(x - a)(x - b - ic)(x - b + ic)
9x³ - 19x² - 17 = (x - a)(x - b - ic)(x - b + ic)
Answer:
b)4 11/10
Step-by-step explanation:
Answer:
-17
Step-by-step explanation:
it's telling you to replace x with -3.
You have to replace all the x's with -3.
(-3)2 + (-3) - 8 = -17
Step-by-step explanation:
Given
w(x) = - 3x - 4
Now
w(7) = - 3 * 7 - 4
= - 21 - 4
= - 25
Hope it will help :)❤
Replace x with -4 so it would be:
f(-4)= 2(-4)=-8
-8 is your answer
