From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.
Using pythagoras theorem,

and

Angle θ is given by

Given that a = 4 units, b = 5 units, and c = 9 units, thus

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.

Given that x is a point on line segment AB, this means that x is a positive number less than 5.
Thus

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
Answer:
x^4-3x^3+x^2-4
Step-by-step explanation:
Given the following functions
R(x) = 2x^4 – 3x^3 + 2x – 1 and
C(x) = x^4 – x^2 + 2x + 3
We are to find the profit function P(x)
P(x) = R(x) - C(x)
P(x) = 2x^4 – 3x^3 + 2x – 1 - ( x^4 – x^2 + 2x + 3)
P(x) = 2x^4 – 3x^3 + 2x – 1 - x^4 + x^2 - 2x - 3
Collect the like terms
P(x) = 2x^4-x^4-3x^3+x^2+2x-2x-1-3
P(x) = x^4-3x^3+x^2+0-4
P(x) = x^4-3x^3+x^2-4
Hence the required profit function P(x) is x^4-3x^3+x^2-4
Answer:
x = 15.3
x = 20.9
Step-by-step explanation:
sin(46) = 11/x
⇒ x = 11/sin(46) = 15.3
cos(55) = 12/x
⇒ x = 12/cos(55) = 20.9
12,571.4286 you subtract 1000 from the total, and divide by 7.
t = 2 → A true
given I = PRT
to find T , divide both sides by PR
note that R = 6% =
= 0.06
T =
= 42/( 350 × 0.06 ) = 2