What is the interquartile range of the data set below? Growth in feet of oak trees: 68,80,73,90,120,94,76,112,101,94,72 (1) 22
sdas [7]
<span>68,80,73,90,120,94,76,112,101,94,72 --->
68, 72, 73, 76, 80, 90, 94, 94, 101, 112, 120
Median = 90
Lower Median = 73
Upper Median = 101
IQR = 101 - 73
IQR = 28</span>
Answer:
C
Step-by-step explanation:
Rbrberbrb
Answer:collecting data
Step-by-step explanation:
Answer:
multiply by 12: r = 18
Step-by-step explanation:
Use the multiplication property of equality. It tells you that multiplying both sides of an equation by the same value does not change the values of any of the variables. Here we can multiply by 12 and we get ...
r(12/12) = 1.5(12)
Now, the properties of the identity element for multiplication come into play. When we multiply r by 12/12=1, we do not change the value of r, so we can simplify this to ...
r = 18
_____
We chose to multiply by 12 precisely because 12/12 = 1, and the result on the left side of the equation is r.
Summarizing the question,
Principle(P)=$100
Rate (r)=12%=0.12
Amount (A)=3×P=$300
Time=t=?
n=no of times the interest is compouned per year=4
Then,
A=P{(1+r/n)}^(n×t)
or,300=100×{1+0.12/4}^(4×t)
or,300/100=(1+0.03)^(4×t)
or,3=1.03^(4×t)
Taking log on both sides,
log3=log[(1.03)^(4×t)]
or,log3= (4×t)×log(1.03)
or,4t=log3/log(1.03)
or,t=log3/[4×log(1.03)]
or, t=9.29175...
t=9.3 years ANS!!!
