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jasenka [17]
3 years ago
13

The diameter of a clock's face is 6 inches. Find the length of the mirror arc formed by the hands of the clock at 4:00. Round to

the nearest hundredth.

Mathematics
1 answer:
Genrish500 [490]3 years ago
6 0
We know that

360°/12 hour-----------> 30°/hour

<span>Central angle at 4 .00 is 120 degrees

the radius of a clock is 6/2-----> r=3 in
length of a circumference=2*pi*r-----> 2*pi*3----> 18.84 in

the minor arc at 4 .00 is  for a central angle of 120</span>°
so
if 360° (full circle)---------> has a length of 18.84 in
 120°----------------------> X
X=120*18.84/360-------> X=6.28 in

the answer is
6.28 in
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36/5= 7⃞5<br> What is the missing the number for the x in the mixed number
Aleks04 [339]

Answer:

Step-by-step explanation:

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Find an equation of a line with the x- and y-intercepts below. Use exact fractions when necessary.
Ludmilka [50]

Answer:

The line with the x- and y-intercepts below has the following equation:

f(x) = \frac{5x}{7} - 5

Step-by-step explanation:

The equation of the line has the following format:

f(x) = ax + b

We are given two points, we are going to substitute them into the above equation, and find the equation of the line given the conditions.

Solution

Starting from the y-intercept makes the solution easier, since the term a is multiplied by 0

y-intercept -5

This means that when x = 0, y = f(x) = -5, so:

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0 = 7(a) - 5

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3 years ago
Which functions are the same as their inverse functions? please help!!!
Whitepunk [10]
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f(x)=[x-1]/[x+5]
step 1
f(x)=y
y=[x-1]/[x+5]
step 2
exchange x for y and y for x
y=[x-1]/[x+5]------> x=[y-1]/[y+5]----> x*[y+5]=[y-1]----> xy+5x=y-1
step 3
clear the variable y
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step 4
f(x)-1= [5x+1]/[1-x]
the function and the inverse function are not the same

case b)
g(x)=[x-2]/[x-1]
step 1
g(x)=y
y=[x-2]/[x-1]
step 2
exchange x for y and y for x
y=[x-2]/[x-1]------> x=[y-2]/[y-1]----> x*[y-1]=[y-2]----> xy-x=y-2
step 3 
clear the variable y
xy-x=y-2-----> xy-y=-2+x----> y*[x-1]=[x-2]----> y=[x-2]/[x-1]
step 4
g(x)-1= [x-2]/[x-1]
the function and the inverse function are  the same

case c)
h(x)=[x+3]/[x-2]
step 1
h(x)=y
y=[x+3]/[x-2]
step 2
exchange x for y and y for x
y=[x+3]/[x-2]------> x=[y+3]/[y-2]----> x*[y-2]=[y+3]----> xy-2x=y+3
step 3 
clear the variable y
xy-2x=y+3-----> xy-y=3+2x----> y*[x-1]=[2x+3]----> y=[2x+3]/[x-1]
step 4
h(x)-1= [2x+3]/[x-1]
the function and the inverse function are not the same

case d)
k(x)=[x+1]/[x-1]
step 1
k(x)=y
y=[x+1]/[x-1]
step 2
exchange x for y and y for x
y=[x+1]/[x-1]------> x=[y+1]/[y-1]---> x*[y-1]=[y+1]----> xy-x=y+1
step 3 
clear the variable y
xy-x=y+1-----> xy-y=x+1----> y*[x-1]=[x+1]----> y=[x+1]/[x-1]
step 4
k(x)-1= [x+1]/[x-1]
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