Answer:
the function is continuous from the left at x=1 and continuous from the right at x=0
Step-by-step explanation:
a function is continuous from the right , when
when x→a⁺ lim f(x)=f(a)
and from the left when
when x→a⁻ lim f(x)=f(a)
then since the functions presented are continuous , we have to look for discontinuities only when the functions change
for x=0
when x→0⁺ lim f(x)=lim e^x = e^0 = 1
when x→0⁻ lim f(x)=lim (x+4) = (0+4) = 4
then since f(0) = e^0=1 , the function is continuous from the right at x=0
for x=1
when x→1⁺ lim f(x)=lim (8-x) = (8-0) = 8
when x→1⁻ lim f(x)=lim e^x = e^1 = e
then since f(1) = e^1=e , the function is continuous from the left at x=1
Answer:
Read left to right
Do parenthesis first
-4 ( 1 + 5) ^2
-4 (6) ^2
Then exponent
6^2 = 6 x 6 = 36
-4 x 36 = -144
Then divide
-144 / 6 = -24
Then the next parenthesis
(42+5) = 47
-24 - 47 = <em>-71</em>
Step-by-step explanation:
Answer:
6
7
8
10
Step-by-step explanation:
you have to remove // to calculate
Answer:
There’s a pretty possible chance this is right 20%
Step-by-step explanation:
