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slavikrds [6]
3 years ago
7

Phoebe wants to get atleast a grade of 90 in the math class. Her grade will be the average of two tests. She scored a 94 on the

first test. write an inequality to represent the situation.
Mathematics
2 answers:
marin [14]3 years ago
7 0
First things first, you will have 94 + x. Place those on top of a fraction bar and on the bottom put the two numbers over 2. So you have 94 + x over 2. Then, write the symbol ‘greater than or equal to’ and on the other side place your 90. So, 90 + x over 2 is greater than or equal to 90. This is a difficult thing to write out and explain so I hope this makes sense. :)
EleoNora [17]3 years ago
5 0

Answer:

x≥86

Step-by-step explanation:

to get at least a 90 she needs an 86, (86+94 or 180)÷2 so x has to be greater than or equal to 86 or x ≥ 86

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mezya [45]
<span>Step 1: 0.06 = 6⁄100</span> 
<span>Step 2: Simplify 6⁄100 = 3⁄50</span><span> 
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Any one good with proportion
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Answer:

4. No

5. No

6. No

7. No

8. No

9a. 2 : 3 = 8 : 12 Extremes: 2, 12. Means: 3, 8

9b. 90 : 36 = 135 : 54 Extremes: 90, 54. Means: 36, 135

Step-by-step explanation:

4. 12 : 25 and 6 : 13 are NOT equal. NO.

5. 64 : 120 = 8 : 15 and 60 : 100 = 3 : 5. NOT equal. NO

6. 37 : 115 and 296 : 966 =  148 : 483. NOT equal. NO

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8. 8 : 10 = 4 : 5 and 11 : 14 are NOT equal. NO.

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9b. 90 : 36 = 135 : 54 Extremes: 90, 54. Means: 36, 1135

6 0
3 years ago
3 • (4 + 5) is how much more than 3 • 4 + 5 ?
IrinaK [193]

Answer:27

Step-by-step explanation:

8 0
3 years ago
17. Evaluate a. 6! b. 8P5 c. 12C4
Andreyy89
The factorial ! just means we multiply by every natural number less that the value so
6! =6×5×4×3×2×1= 720

for permutations we use the formula n!/(n-r)!
so we have 8!/(8-5)!=8!/3!=8×7×6×5×4

for combinations s we have n!/(n-r)!r!
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7 0
3 years ago
Application of Geometric Series
Gnoma [55]

Answer:

  7.2224

Step-by-step explanation:

The value of the summation is given by the formula ...

  Sn = (a1)(1 -r^n)/(1 -r) . . . . . where a1 is the first of n terms, and r is the common ratio.

Your sum has first term and ratio ...

  a1 = 2(0.6) . . . . . summation term for n=1

  r = 0.6

So the sum is ...

  \displaystyle \sum_{n=1}^4{2(0.6^n)}=2(0.6)\dfrac{1-0.6^4}{1-0.6}=\dfrac{1.2}{0.4}(0.8704) = 2.6112

Then the value of the entire given expression is ...

  \displaystyle 2+2\sum_{n=1}^4{}2(0.6^n)=2+2(2.6112)=\boxed{7.2224}

_____

A calculator can help you find the value.

6 0
2 years ago
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