Question

Use synthetic substitution to evaluate the polynomial P(x) = x^3-3x^2+4x-7 for x=3

Answer 1

Answer:

$\frac{x^3-3x^2+4x-7}{x-3} =(x^2+4)+\frac{5}{x-3}$

Step-by-step explanation:

We are given polynomial as

$P(x)=x^3-3x^2+4x-7$

and it is divided by x=3 or x-3

we can use synthetic division

so, we got

Remainder =5

Quotient is

$=x^2+0x+4$

$=x^2+4$

we can write as

$\frac{x^3-3x^2+4x-7}{x-3} =(x^2+4)+\frac{5}{x-3}$