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GREYUIT [131]
3 years ago
13

Can somebody help? Tysm

Mathematics
1 answer:
alukav5142 [94]3 years ago
5 0
X is equal to 8. The work for that is on the attached picture.

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Kendal is doing her science homework. For each problem, she uses 3/4 of a sheet of paper. How many sheets of Will she need to co
Vika [28.1K]
9 sheets of paper I believe 
Have a good day :)
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4 years ago
Where did Hip-Hop get its start?
larisa [96]

Answer:

New York

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Kong took 15, percent fewer seconds than Nolan took to complete his multiplication timed test. Kong took 85
Evgen [1.6K]

Hello!


If Kong took a 85 second and we if Nolan took 15 slower then Nolan took a 72.25 second test. First you would find 14 percent of 85 then that is 12.75. Minus that from 85 and you get 72.25.


Hope It helps!

5 0
3 years ago
A triangle has the following vertices (-1,1), (6,-2)and (3,5) if the scale factor of 3, what will be the vertices of the image
olga2289 [7]

Answer:

  a.  (-3,3), (18,-6), (9,15)

Step-by-step explanation:

If the scale factor is 3 and dilation is about the origin, each of the coordinates of the pre-image is multiplied by 3 to get the coordinates of the image.

Multiplying (-1, 1) by 3 gives (-3, 3), which matches choices A and C.

Multiplying (6, -2) by 3 gives (18, -6) which matches choices A and D.

The only viable choice is choice A.

4 0
3 years ago
Suzanne has a rectangular garden which is 18 feet long and 11 feet wide. She has 168 square foot of paving stones, and she wants
VikaD [51]

Answer:

width = 2.5 feet

Step-by-step explanation:

Suzanne has a rectangular garden which is 18 feet long and 11 feet wide.

Area of the garden = length times width = 18 times 11= 198 square foot

Let 'w' be the width of the border

Length of the garden with border = 18+2w

Width of the garden with border = 11+2w

Area of the garden with border = (18+2w)(11+2w)=4w^2+58w+198

Area of the border = 4w^2+58w+198-198=4w^2+58w

She has 168 square foot of paving stones,

4w^2+58w=168

Solve for w

apply quadratic formula

a= 4, b= 58 and c=-168

\quad x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

w=\frac{-58+-\sqrt{58^2-4\cdot \:4\left(-168\right)}}{2\cdot \:4}

w=\frac{-58+-\sqrt{6052}}{8}

we get two values for w

w=\frac{-58+\sqrt{6052}}{8}=2.47

w=\frac{-58-\sqrt{6052}}{8}=-16.97

5 0
3 years ago
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