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GREYUIT [131]
3 years ago
13

Can somebody help? Tysm

Mathematics
1 answer:
alukav5142 [94]3 years ago
5 0
X is equal to 8. The work for that is on the attached picture.

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What is the perimeter of a polygon with the vertices at (-2,1) (-2,4) (2,7) (6,4) (6,1)?
rusak2 [61]

Answer:

24

Step-by-step explanation:

3 0
3 years ago
I need help someone helps me ASAP please
defon

Answer:

0, 3/4

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l
mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: (\frac{n+1}{2}) th\ term

Putting n=21

(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

<u>For First Half:</u>

98, 100, 101, 102, <u>108, 109</u>, 111,118, 129, 132

Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5

<u>For Second Half:</u>

135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151

Now

<u>Interquartile Range:</u>

IQR = Q_3-Q_1\\= 151-108.5\\=42.5

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

  • brainly.com/question/10940255
  • brainly.com/question/10941043

#LearnwithBrianly

7 0
3 years ago
Stella buys 6 tacos and 4 enchiladas for 52 dollars. Eliana buys 7 tacos and 9 enchilladas for 78 dollars.
Firdavs [7]

Answer:

Let tacos be x and enchiladas be y

6 tacos + 4 enchiladas = 52

becomes

6x+4y=52

^^that's our first equation

Now, the second equation

7 tacos + 9 enchiladas = 78

7x+9y = 78

^^^that's our second equation

Isolate y in the first equation:

6x+4y=52

4y=52-6x

y = (52-6x)/4

^^^Let's call this equation 3

Now, sub-in equation 3 into equation 2

*replace the y*

Equation 2: 7x+9y = 78

Sub-in

7x+ <u>9 ( (52-6x)/4)</u> = 78

Do some algebra (get your x terms on one side) and you will find your x value

7x + <u>117 - 13.5x</u> = 78

(7x-13.5x) = 78-117 *get your x terms on one side

x=6

That's the cost of one taco.

Now, find y. Pick an equation (1,2 or 3). Let's pick 3 since y is already isolated.

All you do is plug in your x value.

Equation 3: y = (52-6x)/4

y= (52 -6(6))/4

...

You should be able to solve this on your own

Step-by-step explanation:

:)) You can solve for y now

5 0
1 year ago
What is 4/5s divided by 2/3s .
Lorico [155]
2/5 no questions :) yesirrr goodluck bro
5 0
2 years ago
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