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amm1812
3 years ago
15

In an engineering test, a rocket sled is propelled into a target. The sled’s distance d in meters from the target is given by th

e formula d = -1.5t2 + 120, where t is the number of seconds after rocket ignition. How many seconds have passed since rocket ignition when the sled is 10 meters from the target?
Mathematics
1 answer:
creativ13 [48]3 years ago
6 0
You're given d = 10
10 = -1.5t<span>2 = 110
</span>t^{2} = 220/3
since t \geq 0
t = \sqrt 220/3
I apologize if this is wrong!
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In the diagram, GH bisects FGI. A. Solve for x and find m FGH. B. Find m HGI. C.find m FGI. A. X=_(simplify your answer)
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Answer:

Part A) x=9 and m∠FGH=29°

Part B) m∠HGI=29°

Part C) m∠FGI=58°

Step-by-step explanation:

Part A) Solve for x and find m∠FGH

we know that

m∠FGI=m∠FGH+m∠HGI

If GH bisects FGI

then

m∠FGH=m∠HGI

substitute the values

4x-7=5x-16

solve for x

5x-4x=16-7

x=9

m∠FGH=4x-7

m∠FGH=4(9)-7=29°

Part B) Find the measure of angle HGI

m∠HGI=5x-16

Remember that

m∠FGH=m∠HGI

Verify

m∠HGI=5(9)-16=29° -----> is correct

Part C) Find the measure of angle FGI

m∠FGI=m∠FGH+m∠HGI

substitute the values

m∠FGI=29°+29°=58°

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Answer:

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Step-by-step explanation:

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So the answer is 13 * 4√3 = 52√3

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