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xeze [42]
3 years ago
10

Can someone help me please

Mathematics
1 answer:
jarptica [38.1K]3 years ago
6 0
Divide the irregular figure into rectangles
Area of rectangle = l * w
4 * 5 = 20 in^2
5 * 12 = 60 in^2
7 * 11 = 77 in^2
Add them together
20 + 60 + 77 = 157 in^2
(Sorry if the picture isn’t neat)

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Simplify <br><br><br> (-4-6i)+(3i)-(8-i)<br><br><br><br> show work please
stich3 [128]
Remove parentheses:

-4 - 6i + 3i - 8 + i
Combine common terms
-12 -2i
4 0
3 years ago
Theresa is making bracelets with beads she has 64 red beads and 40 yellow beads each of the braces will have the same number of
Margaret [11]

Answer:

8 bracelets

Step-by-step explanation:

Given

Yellow = 40 beads

Red = 64 beads

Required

Highest number of bracelets

To answer this question, we simply need to determine the highest common factor of the given parameters.

40 = 2³ * 5

64 = 2⁶

HCF = 2³

HCF = 2 * 2 * 2

HCF = 8

Hence, the maximum number of bracelets is 8

5 0
2 years ago
At Luther's party she made three balloon poodles and two balloon giraffes Which used a total of 17 balloons for Jessica‘s party
olga55 [171]

Answer:

The redaction does not explain the situation.  If we assume that 15 balloons were used to make one ballon poodle and three giraffes, then the answer would be 7,5 balloons for 1 poodle, and 2,5 balloons for a giraffe

Step-by-step explanation:

With 15 balloons we make 1 poodle and 3 giraffes.  This means that 7,5 balloons were used to make 1 poodle, and other 7,5 balloons were used to make 3 giraffes.

If we divide   7,5 balloons between 3, we obtain 2,5.  This means that with 2,5 balloons we make 1 giraffe

4 0
3 years ago
Find the value of x. 10_3 
Lisa [10]
67^o;\ 90^o\ and\ x^o\\angles\ on\ one\ side\ of\ a\ straight\ line\\will\ always\ add\ to\ 180^o.\\\\67^o+90^o+x^o=180^o\\157^o+x^o=180^o\ \ \ \ |subtract\ 157^o\ from\ both\ sides\\\boxed{x^o=23^o}
3 0
3 years ago
Which equation is the inverse of y=100-x2
postnew [5]

Answer:

f^-1(x)=100-x

Step-by-step explanation:


4 0
2 years ago
Read 2 more answers
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