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sladkih [1.3K]
3 years ago
5

Write and Solve a real world problem in which the part of a whole results in a number greater than the whole itself

Mathematics
1 answer:
Agata [3.3K]3 years ago
3 0
That's not physically possible, but this is what I got: 

Draegast had gained 2/3 times as many subscribers as he had before overnight. He had 20/36 as many subs as Pewds. He has 40,000,000 subs.


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Deepak is using blocks to represent the four operation on 8 and 2 witch operation will require the greatest number of blocks
Vadim26 [7]

Answer:

18

Step-by-step explanation:

8 0
3 years ago
10(y+3)-4y please help​
horsena [70]

Answer:6y+30

Step-by-step explanation:

simplify the expression :)<3

5 0
3 years ago
Read 2 more answers
What is the recursive formula for the geometric sequence with this explicit formula?
IRINA_888 [86]

For the given geometric sequence, we have:

a_1 = 9\\\\a_n = (-1/3)*a_{n-1}

So the correct option is B.

<h3>Which is the recursive formula?</h3>

Here we have the geometric sequence:

a_n = 9*(-\frac{1}{3} )^{(n - 1)}

To get the initial value of the geometric sequence, we just need to replace n by 1, so we get:

a_1 = 9*(-\frac{1}{3} )*(1 - 1) = 9

Now, notice that the common ratio is (-1/3), this means that each term of the sequence is (-1/3) times the previous term.

a_n = (-1/3)*a_{n-1}

Then the correct option is B.

If you want to learn more about geometric sequences:

brainly.com/question/1509142

#SPJ1

5 0
2 years ago
The width of the rectangle is 5 inches. The length is twice
olga nikolaevna [1]
Since it’s a rectangle you only need length and width. you have the width which is 5. since the length is twice the width it would be 10 (5x2=10). it’s four sided, so 5+5+10+10=30
6 0
3 years ago
The data represent the results for a test for a certain disease. Assume one individual from the group is randomly selected. Find
sertanlavr [38]

Answer:

The probability of getting someone who tests positive​, given that he or she had the disease is 0.8954.

Step-by-step explanation:

The data provided is:

                  YES        NO    Total

Positive      137           8      145

Negative     16          139    155

Total            153         147    300

An individual is selected at random from the group.

We need to compute the probability of getting someone who tests positive​, given that he or she had the disease.

The conditional probability of an event <em>A</em> given that another event <em>B</em> has already occurred is:

P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{n(A\cap B)}{n(B)}

Let <em>A</em> = individuals who tests positive and <em>B</em> = individual who had the disease.

The number of individuals who tests positive and had the disease is,

n (A ∩ B) = 137

n (B) = 153

Compute the conditional probability of A given B as follows:

P(A|B)=\frac{n(A\cap B)}{n(B)}

            =\frac{137}{153}

            =0.8954

Thus, the probability of getting someone who tests positive​, given that he or she had the disease is 0.8954.

8 0
3 years ago
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