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pogonyaev
3 years ago
5

The perimeter of a square is 28 feet. What is the area of the square?

Mathematics
1 answer:
kati45 [8]3 years ago
7 0
You have to do 7 x 4 because a square has four sides
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Does anyone know the answer to this
Marysya12 [62]
Hello!

We can write this as a proportion below.

\frac{blueprint}{real} = \frac{0.5}{4} = \frac{18}{x}

As you can see, 4 is eight times 0.5. Therefore, we can multiply eighteen by eight to get our answer.

18(8)=144

Just to check, we can cross multiply and divide.

72/0.5=144

Therefore, our answer is 144 feet.

I hope this helps!
3 0
3 years ago
A countertop is 16 feet long and 3 feet wide. Tile costs $28 per square meter. How much will it cost to cover the countertop wit
Butoxors [25]
The area of the counter top is 16 ft by 3 ft so 16 x 3= 48. The area of the counter top is 48 ft squared.Then you have to convert it to meters squared, 48 x 0.092903 = 4.459244. Then multiply that by 28 to get your answer.4.459244 x 28 = 124.861632. The total cost is about $124.86
8 0
3 years ago
Which of the following equations is equivalent to y=2x?
Sloan [31]
First of all, you need to know these two equations:
a^b = c, which also translates into: log a c = b

Now, let us apply these equations here:
a here will stand for 2, b will stand for x, and c will stand for y.
So:

2^x = c, which translates into log2y = x

This means that the equation which is equivalent to y=2x is B. x = log2y
7 0
3 years ago
Read 2 more answers
Which of the following digits could replace the in the ten thousands place to make this statement true? 706,103 rounds to 800,00
Travka [436]

Answer:

numbers <u>5-9</u> could replace the ten thousand place to make the statement true.

<u>5, 7, 8</u>

Step-by-step explanation:

Have a nice day!

7 0
3 years ago
Calculus help! Using the mean value theorem!
marta [7]
f is differentiable across its domain, so the MVT says there is some value of c in the open interval (a,b) such that

f'(c)=\dfrac{f(b)-f(a)}{b-a}

You have

f(x)=Ax^2+Bx+C\implies f'(x)=2Ax+B

so the equation above becomes

2Ac+B=\dfrac{(Ab^2+Bb+C)-(Aa^2+Ba+C)}{b-a}

Solve for c.

2Ac+B=\dfrac{A(b^2-a^2)+B(b-a)}{b-a}
2Ac+B=A(b+a)+B
2Ac=A(b+a)
c=\dfrac{b+a}2

so c is indeed the average of the endpoints, i.e. the midpoint.
8 0
3 years ago
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