Kameryn types 75 words per minute and is just starting to write a term paper. Joe already has 510 words written and types at a s
1 answer:
Answer:
Kameryn will have more words typed than Joe when the number of minutes exceeds 34.
Step-by-step explanation:
Let
x -----> the number of minutes
y ----> the total words typed
we know that
<em>Kameryn</em>
-----> equation A
<em>Joe</em>
-----> equation B
Solve the system of equations by substitution
Substitute equation A in equation B and solve for x
That means
For x=34 minutes
The amount of words written by Kameryn and Joe are the same.
therefore
For x > 34 minutes
Kameryn will have more words typed than Joe when the number of minutes exceeds 34.
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Answer:
Step-by-step explanation:
Given : universal set in this diagram is the set of integers from 1 to 15.
Solution :
The intersection of odd integer,multiples of 3 and Factors of 15 are 3,15
The intersection of odd integer and Factors of 15 are 1,5
The intersection of odd integer,multiples of 3 is 9
The remaining multiples of 3 are 6,12
The remaining odd integers are 7,11,13
Now the remaining integers are 2,4,8,10,14 and these integers must be placed in the boxes outside the circles Since they does not belong any intersection or odd integer or factor of 15 .
Refer the attached figure for the answer.
