What is the solution to the system of equation? -3x-4y-32= -7 2x-6y+2=3 5x-2y+5z=9
2 answers:
Answer:
Step-by-step explanation:
we are given three equation of variable x, y and z.
-3x-4y-3z= -7 ------------- (1)
2x-6y+z=3 ------------- (2)
5x-2y+5z=9 ------------- (3)
- Using elimination method to eliminate z from equation (1) and (2)
Make the coefficient of z same in both equation.
Multiply equation (2) by 3
-3x - 4y - 3z = -7
6x - 18y + 3z = 9
Add above equation to eliminate z
3x - 22y = 2 ---------------(4)
- Using elimination method to eliminate z from equation (2) and (3)
Make the coefficient of z same in both equation.
Multiply equation (2) by -5
-10x + 30y - 5z = -15
5x - 2y + 5z = 9
Add above equation to eliminate z
-5x + 28y = -6 ---------------(5)
- Using elimination method to eliminate x from equation (4) and (5)
Make the coefficient of x same in both equation.
Multiply equation (4) by 5 and equation (5) by 3
15x - 110y = 10
-15x + 84y = -18
Add above equation to eliminate x
-26y = -8
Substitute y into equation (5) to get x
So,
Substitute x and y into equation (1)
Solution:
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