Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s tandard form. 3, -13, and 5 + 4i
1 answer:
Complex zeros exist in conjugate pairs so the fourth zero is 5 - 4i So we have P(x) = ( x - 3)(x + 13)(x - (5 + 4i))(x - (5 - 4i)) = (x - 3)(x + 13)( x - 5 - 4i)(x - 5 + 4i) = (x^2 + 10x - 39)(x^2 - 5x + 4ix - 5x + 25 -20i - 4ix + 20i -16i^2) = (x^2 + 10x - 39)(x^2 - 10x + 41) = x^4 - 10x^3 + 41x^2 + 10x^3 - 100x^2 + 410x - 39x^2 + 390x - 1599 = x^4 - 98x^2 + 800x - 1599 Answer
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The answer is:
Let the width = x the length = x+7 => Area equation = length x width = x(x+7) = x^2 +7x = 78 => x^2+7x -78 = 0 => (x-6)(x+13)=0 => x=6 or x=-13(no) => the width = 6 m => the length = 6+7= 13 m
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250÷20= 12.5 round it up to 13 so 13 months
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