Group points {(0,1),(0,5)(2,6),(3,3)}is not a function, but group points {(1,4)(2,7)(3,1)(5,7)} is a function. What do you notic
Tasya [4]
<h2>Any value in the domain of the function should have a unique value in codomain.</h2>
Step-by-step explanation:
In the first set of points 
,
value 
maps to two distinct values 
in the codomain.
This violates the property of functions.
The first set of points does not form a function.
In the second set of points 
,
Every value in domain corresponds to unique value in domain.
There is no violation in the property of functions.
The second set of points does form a function.
Okay as dumb=b as it sounds, i have the answer but i cannot type it out on the computer..... the way i got this answer was through an app called "photomath". download it!! trust me you wont be disappointing because you can solve formulas like this<span />
Answer:
Just find the line with a rise of 1 and a run of 4.
Step-by-step explanation:
To find a line first find a actual point that connects and just go up 1 and go to the right of 4. It has to go right becuase since it’s a positive slope it’d have to go right for the run. FInd a point go up 1 and right 4 and if the results gets you landed on a another point, you have suceded to find the graph with A s lope of 1/4
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
(2u+3u)(u+v)-2u+3v
=2u(u+v)+3u(u+v)-2u+3v
=2u^2+2uv+3u^2+3uv-2u+3v
=5u^2+5uv-2u+3v
