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Len [333]
3 years ago
8

Use parametric equations to find the inverse of y=x^2-x-6

Mathematics
1 answer:
jenyasd209 [6]3 years ago
5 0
I would start by using completing the square to rewrite the function 'y' in vertex form:

y+6+\frac{1}{4} = (x- \frac{1}{2})^2 \\  \\ y+\frac{25}{4} = (x- \frac{1}{2})^2

Now since you want the inverse, swap the x,y variables

x+\frac{25}{4} = (y- \frac{1}{2})^2

Make a substitution to introduce parameter 't'.

t = y - \frac{1}{2}

Therefore
x = t^2 - \frac{25}{4}\\ \\ y = t + \frac{1}{2}
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