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Len [333]
3 years ago
8

Use parametric equations to find the inverse of y=x^2-x-6

Mathematics
1 answer:
jenyasd209 [6]3 years ago
5 0
I would start by using completing the square to rewrite the function 'y' in vertex form:

y+6+\frac{1}{4} = (x- \frac{1}{2})^2 \\  \\ y+\frac{25}{4} = (x- \frac{1}{2})^2

Now since you want the inverse, swap the x,y variables

x+\frac{25}{4} = (y- \frac{1}{2})^2

Make a substitution to introduce parameter 't'.

t = y - \frac{1}{2}

Therefore
x = t^2 - \frac{25}{4}\\ \\ y = t + \frac{1}{2}
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which expression represents the amount of money john has collected? john collects $5 for club dues from each member.
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5.00x (number of people)
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Which polynomial is prime? x3 + 3x2 – 2x – 6 x3 – 2x2 + 3x – 6 4x4 + 4x3 – 2x – 2 2x4 + x3 – x + 2
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What is the sum of the first 5 terms of this geometric series? Use . -4 + 12 + (-36) + ⋯
yKpoI14uk [10]

Answer:

The sum of the first 5 terms is -244

Step-by-step explanation:

To calculate the sum of the geometric series, we need the first term, the common ratio and the number of terms we would like to sum.

The first term here is -4

The common ratio is T2/T1 or T3/T2 = 12/-4 = -3

number of terms n = 5

The formula to use is;

Sn = a(1-r^n)/(1-r)

Plugging these values, we have;

Sn = -4(1-(-3)^5)/(1-(-3))

Sn = -4(1+243)/4 = -1(244) = -244

7 0
3 years ago
Factor 121m^2-198m+81
Pie

<u>1) Rewrite it in the form a^2-2ab+b^2, where a=11m and b=9</u>

(11m)^2-2(11m)(9)+9^2

<u>2) Use Square of Difference: (a-b)^2=a^2-2ab+b^2</u>

(11m-9)^2

<u>Your answer is (11m-9)^2</u>

5 0
3 years ago
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