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777dan777 [17]
3 years ago
10

Nadia needs 2/5 cup of orange juice for a punch recipe. She will double the recipe to make punch for a party. Which statement is

true?
Mathematics
1 answer:
adelina 88 [10]3 years ago
3 0

Answer:

Step-by-step explanation:

There's not a lot to go on with the details provided in the question, but based on all you said, if there isn't more to the question, then the true statement is the fact that Nadia needs 2/5 cup of orange juice for punch recipe.

Twice that amount is 4/5, and logically, that can't suffice in a party, except it's a party of 3, maybe 5 people. I'm assuming the people in the party would be much more than that. Makes the fraction impossible

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Easton wants to put a variety of donuts in a display case. The case is large enough to hold 100 donuts. Complete the table below
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The amounts for each donut are given as follows:

  • Strawberry: 15.
  • Chocolate: 45.
  • Sprinkle: 40.

<h3>How to obtain the amounts?</h3>

The amounts for each donut are found applying the proportion, multiplying the decimal equivalent of each percentage by the total number of donuts.

From the problem, the total number of donuts is given as follows:

100 donuts.

The percentages of each type of donuts are given as follows:

  • Strawberry: 15%.
  • Chocolate: 45%.
  • Sprinkle: 40%.

The decimal equivalent of each percentage is given as follows:

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  • Sprinkle: 0.4.

Hence the amounts are given as follows:

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  • Sprinkle: 40, as 0.4 x 100 = 40.

More can be learned about proportions at brainly.com/question/24372153

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1 year ago
Mr grain left for work at 7:15 am. twenty five mintutes later he aririved at his work. what time did mr giarmo arrive at his
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The factors of the number 56 are 1, 2, 4, 7, 8, 14, 28, and 56. Choose the factor pairs of the number 56.
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Answer:

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d) 2×28

Step-by-step explanation:

A factor pair of a number is a pair of numbers that, when multiplied will result in the given number.

The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, and 56.

The factor pairs are:

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Out of the options, only Option A is not a factor pair.

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