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julia-pushkina [17]
3 years ago
12

I need help with math

Mathematics
1 answer:
Stels [109]3 years ago
5 0
1/2 of an acre per hour
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A pet store has 150 goldfish and betta fish altogether. The ratio of goldfish to betta fish is 2:3. How many goldfish does the p
Kipish [7]

The number of goldfish in the pet store is equal to 60 fishes.

  • Let the goldfish be G.
  • Let the betta fish be B.

<u>Given the following data:</u>

  • Total number of fishes = 150 fishes.
  • Ratio of G to B = 2:3
  • Total ratio= 2 + 3 = 5

To calculate the number of goldfish that the pet store have:

<h3>What is ratio?</h3>

Ratio can be defined as an expression that is used to denote the proportion of two (2) or more quantities with respect to one another and the total quantities.

Mathematically, the number of goldfish in the pet store is given by this expression:

G = \frac{2}{5} \times 150\\\\G=0.4 \times 150

G = 60 fishes.

Read more on ratio here: brainly.com/question/13513438

6 0
2 years ago
Read 2 more answers
A. Is the sum of two polynomials always a polynomial? Explain
IgorLugansk [536]

Answer:  The answers for both (a) and (b) is YES.


Step-by-step explanation: A polynomial is an algebraic expression containing   two or more algebraic terms, i.e., the sum of several terms that contain different powers of the same variable or variables with real coefficients.

For example, p(x) = 4x²+x+2 is a polynomial in variable 'x'.

(a) Yes, the sum of two polynomials is again a polynomial. For example,

if p(x) = ax² + bx + c  and  q(x) = dx² + ex + f, where, a, b, c, d, e and f are real numbers, then their sum will be

p(x) + q(x) = (a+d)x²+(b+e)x+(c+f), which is again a polynomial in 'x' with real coefficients.

(b) Yes, the difference of two polynomials is again a polynomial. For example,

p(x) - q(x) = (a-d)x²+(b-e)x+(c-f), which is again a polynomial in 'x' with real coefficients.

Thus, the answer is YES.

6 0
3 years ago
(3m2n4)3 the 2/4/3 are the small numbers
lesya692 [45]

Answer:

what

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
calculate how much 1% salt solution must be mixed with how much 5% salt solution to make 100 milliliters of 2% salt solution. yo
Setler79 [48]
Let x be the amount (the volume in milliliters) of the 5% solution to be mixed.

Then the volume of the 1% solution is 100-x milliliters.


Then your "concentration" equation is

%280.01%2A%28100-x%29+%2B+0.05%2Ax%29%2F100 = 0.02,


or, equivalently,

100-x + 5*x = 200,

which implies

4x = 100 ----> x = 100%2Fx = 25.


Answer: 25 milliliters of the 5% solution must be mised with 100-25 = 75 milliliters of the 1% solution.
7 0
3 years ago
PLEASE HELP MEEEEE!! WILL MARK BRAINLIST!!
Lynna [10]
I believe the answer is D, I’m almost 100% positive this is correct
6 0
3 years ago
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