And improper fractions with a denominator of 4 could be..
This is because 34 over 4 simplifies to 8
I know it simplifies to 8 because 32 ÷ 4 is 8
8 is in between 5 and 10 as well
5∠ 8 ∠10
The solution for x is equal to x = (4 · y) / (r + 6).
<h3>How to find an explicit solution of an algebraic equation</h3>
In this problem we have an equation formed by three variables (r, x, y) and a constant and we are asked to clear x as a function of r and y. Now we present the entire procedure:
(r · x + 6 · x) / y = 4 Given
(r · x + 6 · x) = 4 · y Defintion of division / Associative property / Compatibility with multiplication / Existence of multiplicative inverse / Modulative property
x · (r + 6) = 4 · y Distributive property
x = (4 · y) / (r + 6) Compatibility with multiplication / Associative property / Existence of multiplicative inverse / Modulative property / Definition of division / Result
The solution for x is equal to x = (4 · y) / (r + 6).
To learn more on equations: brainly.com/question/10413253
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Momentum =mass x velocity
therefore
velocity=184 divide by 92 = 2 m/s
Answer:
2(d-vt)=-at^2
a=2(d-vt)/t^2
at^2=2(d-vt)
Step-by-step explanation:
Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula, d is
displacement, v is final velocity, a is acceleration, and t is time.
Given the formula for calculating the displacement of a body as shown below;
d=vt - 1/2at^2
Where,
d = displacement
v = final velocity
a = acceleration
t = time
To make acceleration(a), the subject of the formula
Subtract vt from both sides of the equation
d=vt - 1/2at^2
d - vt=vt - vt - 1/2at^2
d - vt= -1/2at^2
2(d - vt) = -at^2
Divide both sides by t^2
2(d - vt) / t^2 = -at^2 / t^2
2(d - vt) / t^2 = -a
a= -2(d - vt) / t^2
a=2(vt - d) / t^2
2(vt-d)=at^2
