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marshall27 [118]
3 years ago
9

I've been having problems with this for a while...

Mathematics
1 answer:
Rina8888 [55]3 years ago
3 0
Like all problems that involve images within the question, we should definitely try to draw this out. In the picture above, I have done this.

Now, we can see that this is just a simple proportion problem. For every 2.5 cm of height of the flower, we are 2 cm from the opening, or aperture. For every 20 cm of height, how far are we? We can set up the problem like this:

20 ............2.5
-------- = ---------
...x ............. 2

where x is the unknown distance to the aperture from the flower. Now, we just need to get x by itself. A typical way of solving something like this is by doing "butterfly multiplication" which is really just a shortcut haha. Anyway, I can rewrite that equation ^ as:

20×2 = 2.5 × x

Then, to solve for x, we would divide both sides by 2.5. (If you don't know why that is, please let me know and I'll elaborate).

We would then have:

20×2
------- = x
2.5

Which then simplifies to:

x = 16

Try using the same logic for your second question, and if you get stuck, I'd be happy to help! please let me know if any of this doesn't make sense. :)

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Solve the systems of equations using substitution. <br> -3x + 2y = 12<br> x = 2y - 8
ankoles [38]

-3(2y-8) + 2y = 12

-4y + 24 = 12

-4y = -12

y=3

x=2(3)-8

x=-2

4 0
3 years ago
A line of roses forms the diagonal of a rectangular flower garden. Th e line of roses is 18.4 m long, and one side of the garden
professor190 [17]
Given that the garden is rectangular and a line of roses form the diagonal 18.4 m long, we required to calculate the length of the perpendicular side.
Here we shall use the Pythagorean theorem.
c²=a²+b²
where c is the hypotenuse, a and b are the legs.
from the information given:
c=18.4 m
a=13 m
plugging this into our expression we get:
18.4²=13²+b²
next we solve for the value of b
b²=18.4²-13²
b²=338.56-169
b²=169.56
b=√169.56
b=13.0215
hence the length to the nearest tenth of a meter will be approximately 13.0 m
6 0
3 years ago
Match each system of linear equations to its solution. A. (5, –6) b. (–2, 8) c. no solution d. (3, 1) e. (2, –8) f. (4, –1) g. i
almond37 [142]

Answer:

NOT SURE HOLD ON

Step-by-step explanation:

7 0
3 years ago
Can someone help me???
chubhunter [2.5K]

Answer: 193.3125

Step-by-step explanation:

It deleted my entire explanation um-

Anyways, calculate the area of the rectangle, length x width (7 * 15) and the semicircle (i did pi times radius squared and halved it to get the semicircle)

Basically, 105 plus the semicircle is 193.

4 0
3 years ago
Find the values of the sine, cosine, and tangent for ZA.<br><br> (TOP OF TRIANGLE IS (A))
Sloan [31]

\bigstar\:{\underline{\sf{In\:right\:angled\:triangle\:ABC\::}}}\\\\

  • AC = 7 m
  • BC = 4 m

⠀⠀⠀

\bf{\dag}\:{\underline{\frak{By\:using\:Pythagoras\: Theorem,}}}\\\\

\star\:{\underline{\boxed{\frak{\purple{(Hypotenus)^2 = (Perpendicular)^2 + (Base)^2}}}}}\\\\\\ :\implies\sf (AB)^2 = (AC)^2 + (BC)^2\\\\\\ :\implies\sf (AB)^2 = (AB)^2 = (7)^2 = (4)^2\\\\\\ :\implies\sf (AB)^2 = 49 + 16\\\\\\ :\implies\sf (AB)^2 = 65\\\\\\ :\implies{\underline{\boxed{\pmb{\frak{AB = \sqrt{65}}}}}}\:\bigstar\\\\

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━

☆ Now Let's find value of sin A, cos A and tan A,

⠀⠀⠀

  • sin A = Perpendicular/Hypotenus = \sf \dfrac{4}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{4 \sqrt{65}}{65}}

⠀⠀⠀

  • cos A = Base/Hypotenus = \sf \dfrac{7}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{7 \sqrt{65}}{65}}

⠀⠀⠀

  • tan A = Perpendicular/Base = {\sf{\pink{\dfrac{4}{7}}}}

⠀⠀⠀

\therefore\:{\underline{\sf{Hence,\: {\pmb{Option\:A)}}\:{\sf{is\:correct}}.}}}

4 0
2 years ago
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