Answer:
Therefore the Perimeter of the room is 94 ft.
Step-by-step explanation:
Given:
Where ,
P = Perimeter
l = Length = 26 ft
w = Width = 21 ft
To Find:
Perimeter of the room = ?
Solution:
Perimeter of Rectangle is given as
Substituting 'l' and 'w' we get
Therefore the Perimeter of the room is 94 ft.
Answer:
1. A = 40 units²
2. A = 72 units²
3. B) 45
Step-by-step explanation:
1. This shape comprises 4 congruent triangles with base of 5 units and height of 5 units.
Area of a triangle = 1/2 x base x height
Therefore, area of polygon = 4(1/2 x 5 x 4)
= 40 units²
2. This shape comprises two pairs of congruent triangles.
Area of a triangle = 1/2 x base x height
Therefore, area of polygon = 2(1/2 x 2 x 6) + 2(1/2 x 10 x 6)
= 72 units²
3. Count the number of shaded squares:
9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 45 units²
<span>There are several ways to do this problem. One of them is to realize that there's only 14 possible calendars for any year (a year may start on any of 7 days, and a year may be either a leap year, or a non-leap year. So 7*2 = 14 possible calendars for any year). And since there's only 14 different possibilities, it's quite easy to perform an exhaustive search to prove that any year has between 1 and 3 Friday the 13ths.
Let's first deal with non-leap years. Initially, I'll determine what day of the week the 13th falls for each month for a year that starts on Sunday.
Jan - Friday
Feb - Monday
Mar - Monday
Apr - Thursday
May - Saturday
Jun - Tuesday
Jul - Thursday
Aug - Sunday
Sep - Wednesday
Oct - Friday
Nov - Monday
Dec - Wednesday
Now let's count how many times for each weekday, the 13th falls there.
Sunday - 1
Monday - 3
Tuesday - 1
Wednesday - 2
Thursday - 2
Friday - 2
Saturday - 1
The key thing to notice is that there is that the number of times the 13th falls upon a weekday is always in the range of 1 to 3 days. And if the non-leap year were to start on any other day of the week, the numbers would simply rotate to the next days. The above list is generated for a year where January 1st falls on a Sunday. If instead it were to fall on a Monday, then the value above for Sunday would be the value for Monday. The value above for Monday would be the value for Tuesday, etc.
So we've handled all possible non-leap years. Let's do that again for a leap year starting on a Sunday. We get:
Jan - Friday
Feb - Monday
Mar - Tuesday
Apr - Friday
May - Sunday
Jun - Wednesday
Jul - Friday
Aug - Monday
Sep - Thursday
Oct - Saturday
Nov - Tuesday
Dec - Thursday
And the weekday totals are:
Sunday - 1
Monday - 2
Tuesday - 2
Wednesday - 1
Thursday - 2
Friday - 3
Saturday - 1
And once again, for every weekday, the total is between 1 and 3. And the same argument applies for every leap year.
And since we've covered both leap and non-leap years. Then we've demonstrated that for every possible year, Friday the 13th will happen at least once, and no more than 3 times.</span>
Answer:
Its Not C or B, tried em and got em wrong
Step-by-step explanation:
<h2>Writing an Equation of a Line in Slope-Intercept Form</h2><h3>
Answer:</h3>
![y = [ -2 ] x + [ 1 ]\\](https://tex.z-dn.net/?f=y%20%3D%20%5B%20-2%20%5D%20x%20%2B%20%5B%201%20%5D%5C%5C)
<h3>
Step-by-step explanation:</h3>
<em>Please refer to my answer from this Question to know more about Slope-Intercept Form: <u>brainly.com/question/24599351</u></em>
We must first find the slope.
<em>Please refer to my Answer from this Questions to know more about Slopes of a Line:</em>
We can see the marked points, 
and 
, are on the line.
Solving for the slope:
Now we can now solve for the 
-intercept.
<em>Please refer to the second paragraph of my Answer from this Question to know more about y-intercepts: <u>brainly.com/question/24606058</u></em>
We can see that the line intersected the -axis at so 
.
