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2 years ago

24is 40% of what number? Use the percent eqation.

Mathematics

1 answer:

scoray [572]2 years ago

4 0

Answer:

Step-by-step explanation:

40%=0.40

0.4x=24

x=24/0.4

x=60

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A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co

butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

$\displaystyle \vec{v}=\frac{\vec{x}}{t}$

Where $\vec x$ is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

$\displaystyle \vec{x}=\vec{v}.t$

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

$\displaystyle \vec{v_1}=$

$\displaystyle \vec{v_1}=\ km/h$

The displacement of the plane in 2 hours is

$\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)$

$\displaystyle \vec{x_1}=km$

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

$\displaystyle \vec{v_2}=$

$\displaystyle \vec{v_2}=km/h$

The displacement in 1 hour is

$\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)$

$\displaystyle \vec{x_2}=km$

The total displacement is the vector sum of both

$\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+$

$\displaystyle \vec{x_t}=km$

$\displaystyle \vec{x_t}=$

The distance from the airport is the module of the displacement:

$\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}$

$\displaystyle |\vec{x_t}|=894.43\ km$

8 0

3 years ago

Find angle <QPS in the diagram

marin [14]

Answer:

40°

Step-by-step explanation:

Because triangle QSR is isosceles ∠SQR=∠SRQ=35°. The sum of the angles in a triangle is 180°, so ∠QSR=180°-35°-35°=110°. The measure of a straight line is 180°, so ∠PSQ=180°-110°=70°. Because triangle PSQ is also isosceles ∠PSQ=∠PQS=70°. Then, ∠QPS=180°-70°-70°=40°.

4 0

2 years ago

What is the equivalent expression after this is simplified

mafiozo [28]

Answer: -6 - 5k

Step-by-step explanation:

-3(2+4k) +7(2k-1)

-6+(-12k) + 14k -7k

-6 -12k + 14k - 7k

-6 -5k

8 0

3 years ago

Read 2 more answers

What is the solution to this system of linear equations?2x + y = 13x – y = –6(–1, 3)(1, –1)(2, 3)(5, 0)

worty [1.4K]

$\underline{+\left\{\begin{array}{ccc}2x+y=1\\3x-y=-6\end{array}\right}\ \ \ \ |\text{add both sides of equations}\\.\ \ \ \ \ 5x=-5\ \ \ \ |:5\\.\ \ \ \ \ \ x=-1\\\\\text{put the value of x to the first equation}\\\\2(-1)+y=1\\-2+y=1\ \ \ |+2\\y=3\\\\\text{Answer:}\ (-1,\ 3)$

5 0

3 years ago

PLEEEEEEEAAAAAAASSSSSSSSSSEEEEEEEEEEE help me!!!!!!!!!!

defon

Answer:

$\boxed{\sf \ \ \ \dfrac{18}{(x-7)(x+12)(x+30)} \ \ \ }$

Step-by-step explanation:

hello,

first of all we will study the quadratic expressions

we can write that, (the different answers provide good clues :-) )

$x^2+5x-84=(x-7)(x+12)$

and

$x^2+23x-210=(x-7)(x+30)$

so first of all as we cannot divide by 0 we need to take x different from 7, -12 and -30 and then we can write

$\dfrac{1}{x^2+5x-48}-\dfrac{1}{x^2+23x-210}=\dfrac{1}{(x-7)(x+12)}-\dfrac{1}{(x-7)(x+30)}\\\\=\dfrac{(x+30) -(x+12)}{(x-7)(x+12)(x+30)}=\dfrac{x+30-x-12}{(x-7)(x+12)(x+30)}\\\\=\dfrac{18}{(x-7)(x+12)(x+30)}$

hope this helps

7 0

3 years ago