Correction:
I think the question should be like that find the approximate value of
P(-0.78 < z < 1.16)?
Now,
the symbol Ф represent the cumulative density.
first find the
Ф(1.16) from the above given table which is equal to 0.8770.
Now,
find the Ф(-0.78) .
in our table we are given the value of Ф(0.78)=0.7823
so as the curve is symmetrical Ф(-0.78)=1-0.7823=0.2177
P(-0.78 < z < 1.16) = Ф(1.16)-Ф(-0.78)
= 0.8770-0.2177
= 0.6593
The distance between Branch A and Branch B is given by the Pythagoras theorem
AB² = (Vertical Distance)² + (Horizontal Distance)²
AB² = (4-1)² + (1 - -3)²
AB² = 3² + 4²
AB² = 9 + 16
AB² = 25
AB = 5
BC² = (Vertical distance)² + (Horizontal distance)²
BC² = (-2 - 4)² + (5-1)²
BC² = (-6)² + (4)²
BC² = 36 + 16
BC² = 52
BC = 7.21
Half way of BC = 7.21 ÷ 2 = 3.6 miles
Total distance travelled from A to B and then halfway from B to C is 3.6+5 = 8.6 miles
Nine hundred and seventeen point twenty seven
7x (2x^2 - 3) is your answer my dude/lady
27 times 3= 81 then add 9 which then equals 89
