Answer:
The larger number is -6, the smaller number is -15
Step-by-step explanation:
We have two numbers, a and b.
We know that one number is larger than another by 9.
Then we can write:
a = b + 9
then a is larger than b by 9 units.
If the greater number is increased by 10 (a + 10) and the lesser number is tripled (3*b), the sum of the two would be -41:
(a + 10) + 3*b = -41
So we got two equations:
a = b + 9
(a + 10) + 3*b = -41
This is a system of equations.
One way to solve this is first isolate one variable in one of the two equations:
But we can see that the variable "a" is already isolated in the first equation, so we have:
a = b + 9
now we can replace that in the other equation:
(a + 10) + 3*b = -41
(b + 9) + 10 + 3*b = -41
now we can solve this for b.
9 + b + 10 + 3b = -41
(9 + 10) + (3b + b) = -41
19 + 4b = -41
4b = -41 -19 = -60
b = -60/4 = -15
b = -15
then:
a = b + 9
a = -15 + 9 = -6
a = -6
Answer:
vertical asymptote is: x=4
horizontal asymptote is: y=1
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Answer:
first term = 2 ...(given)
second term = f (2) = f (2-1) * 5 = 1 * 5 = 5. .....[according to the formula f(n) = f (n -1) *5 ]
third term = f (3) = f ( 3 - 1 ) * 5 = 2 * 5 = 10
fourth term = f (4) = f (4 - 1) * 5 = 3 * 5.= 15
fivth term = f (5) = f ( 5 - 1) * 5 = 4* 5. =20
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