Congruent because 2 is a larger number then one and 1 is a smalled number then 2
Answer:
Below.
Step-by-step explanation:
I won't do all of these for you but I'll show you the general method.
First write each number as prime factors.
For example number 7:
LCM of 24 and 34.
24 = 2 * 2 * 2 * 3
34 = 2 * 17
The LCM is the multiple of all these factors EXCEPT if there is a duplicate number you only use it once.
There is one duplicate here - the 2 ( in bold) so we only use this once.
So the LCM = 2 * 2 * 2 * 3 * 17 = 408.
Number 1:
13, 25
13 = 13
25 = 5 * 5
There are no duplicates so the LCM = 13 * 5 * 5 = 325.
Number 18:
15, 84
15 = 3 * 5
84 = 2 * 2 * 3 * 7
Number 3 is common to both sets so it is only used once:
LCM = 2 * 2 * 3 * 5 * 7 = 420.
Number 40:
18, 48
18 = 2 * 3 * 3
48 = 2 * 2 * 2 * 2 * 3
There are 2 sets of duplicates here, 2 and 3 .
LCM = 2 * 2 * 2* 2 * 3 * 3 = 144.
Answer: 
Step-by-step explanation:
Given
Taylor has nickels and dimes
Number of nickels is 7 less than eight times the number of dimes
If d is the number of dimes, then number of nickels is given by

Answer:
79 = 13+15+24+ missing side. 79 = 52 + missing side
32 = x ⇒ write 32 as a power of 2
2⁵ = x
Then apply the log rule

⇒

We have 2⁵ = x
The 'a' is the digit '2'
The 'b' is the digit ''x
The 'c' is the digit '5'
Write this as a logarithm expression, we have