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Bezzdna [24]
3 years ago
5

Amber is solving this problem. 252 × 605.

Mathematics
2 answers:
expeople1 [14]3 years ago
6 0
The answer would be A
babunello [35]3 years ago
3 0
The answer while be a
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Each day, X arrives at point A between 8:00 and 9:00 a.m., his times of arrival being uniformly distributed. Y arrives independe
astraxan [27]

Answer:

Y will arrive earlier than X one fourth of times.

Step-by-step explanation:

To solve this, we might notice that given that both events are independent of each other, the joint probability density function is the product of X and Y's probability density functions. For an uniformly distributed density function, we have that:

f_X(x) = \frac{1}{L}

Where L stands for the length of the interval over which the variable is distributed.

Now, as  X is distributed over a 1 hour interval, and Y is distributed over a 0.5 hour interval, we have:

f_X(x) = 1\\\\f_Y(y)=2.

Now, the probability of an event is equal to the integral of the density probability function:

\iint_A f_{X,Y} (x,y) dx\, dy

Where A is the in which the event happens, in this case, the region in which Y<X (Y arrives before X)

It's useful to draw a diagram here, I have attached one in which you can see the integration region.

You can see there a box, that represents all possible outcomes for Y and X. There's a diagonal coming from the box's upper right corner, that diagonal represents the cases in which both X and Y arrive at the same time, under that line we have that Y arrives before X, that is our integration region.

Let's set up the integration:

\iint_A f_{X,Y} (x,y) dx\, dy\\\\\iint_A f_{X} (x) \, f_{Y} (y) dx\, dy\\\\2 \iint_A  dx\, dy

We have used here both the independence of the events and the uniformity of distributions, we take the 2 out because it's just a constant and now we just need to integrate. But the function we are integrating is just a 1! So we can take the integral as just the area of the integration region. From the diagram we can see that the region is a triangle of height 0.5 and base 0.5. thus the integral becomes:

2 \iint_A  dx\, dy= 2 \times \frac{0.5 \times 0.5 }{2} \\\\2 \iint_A  dx\, dy= \frac{1}{4}

That means that one in four times Y will arrive earlier than X. This result can also be seen clearly on the diagram, where we can see that the triangle is a fourth of the rectangle.

6 0
3 years ago
write an equation to represent the relationship, and find the amount of peanut butter used to make 25 cracker packages. the tabl
Nadusha1986 [10]

We are given 4 points.

(\frac{1}{2},2)

(\frac{5}{8},\frac{5}{2})

(\frac{3}{4},3)

(\frac{7}{8},\frac{7}{2})

Using this, we can make an equation.

y=4x

I got m=4 by using the slope formula.

m=\frac{2.5-2}{0.625-0.5}

m=\frac{0.5}{0.125}

m=4

So the equation we have is y=4x

Now, we can solve for how much peanut butter is used to make 25 packages by plugging in 25 for y, which is the number of cracker packages.

25=4x

x=\frac{25}{4}

We need to use \frac{25}{4} teaspoons of peanut butter to make 25 packages of crackers.

Hope this helps.

頑張って!

4 0
3 years ago
Hi, help ASAP please.
Kisachek [45]

Answer:

17.3

Step-by-step explanation:

50 - 32.7 = 17.3

7 0
2 years ago
Simplify: square root of 81+18<img src="https://tex.z-dn.net/?f=%5Csqrt%7B7%7D" id="TexFormula1" title="\sqrt{7}" alt="\sqrt{7}"
Lemur [1.5K]

\sqrt{81 \:  +  \: 18 \sqrt{7}  \:  +  \: 7}

  • Factor the indicated expression:

\sqrt{(9 \:  +  \:  \sqrt{7} ) ^{2} }

  • Simplified the index, the root and also the exponent using the number 2.

\boxed{ \bold{9 \:  +  \:  \sqrt{7} }}

<h3><em><u>MissSpanish</u></em> </h3>
5 0
2 years ago
5. Solve 2(1 - x) &gt; 2x.
Mrrafil [7]

Answer:

I do not know for sure but i think it might be B.

Step-by-step explanation:

Im not the smartest so yeah hopefully that is the answer you are looking for tho :D

4 0
3 years ago
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