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gogolik [260]
3 years ago
15

There are 4 squares and 6 circles. What is the simplest ratio of squares to circles?

Mathematics
1 answer:
MakcuM [25]3 years ago
8 0

Answer:

2 : 3

Step-by-step explanation:

We have 4 squares and 6 circles. We would like the ratio of squares to circles, so we divide 4 by 6:

4 / 6  ⇒  the ratio here would be 4 : 6

We need to simplify this. Notice that both 4 and 6 are divisible by 2. So, we can divide both by 2:

4/2 : 6/2  ⇒  2 : 3

2 and 3 don't share any factors other than 1, so we leave the ratio like this.

The answer is thus 2 : 3.

<em>~ an aesthetics lover</em>

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Divide.<br> X^2-4/x-8/x-2
defon
I must assume you mean: 

[(x^2 - 4) / (x - 8)] / [x - 2] -----> express this way: 

[(x^2 - 4)] / [(x - 8)(x - 2)] 

But x^2 - 4 = x^2 - 2^2, which is a difference of squares: a^2 - b^2 = (a + b)(a - b) -----> 

[(x + 2)(x - 2)] / [(x - 8)(x - 2)] -----> (x - 2) gets cancelled out -----> 

(x + 2) / (x - 8) 

<span>That's your answer. I hope this helps

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
3 0
3 years ago
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AleksAgata [21]

% means per 100

so when figuring out percents it's good to use 100

so

on $100 7% would mean $7

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6 0
3 years ago
Will give brainliest to correct answer.
Alika [10]

The Pyth. Thm. applies here:


(√x + 1)^2 + (2√x)^2 = (2√x + 1 )^2


Expanding the squares:


x + 2sqrt(x) + 1 + 4x = 4x + 4sqrt(x) + 1


Let's subtract x + 2sqrt(x) + 1 + 4x from both sides:


4x + 4sqrt(x) + 1

-(x + 2sqrt(x) + 1 + 4x)

-------------------------------

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Then 2sqrt(x) = x


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Check these results by substitution. Does the Pyth. Thm. hold true for x=4?

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Answer:

Step (2) is incorrect.

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The area of a rectangle is given by :

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It means he has done a mistake in step (2). The correct step should be 4(2) + 4(3x).

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USPshnik [31]
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3 years ago
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