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2 years ago

Write the equation 0.3x 2 + 5x - 7 = 0 in general form and then choose the value of "b."

Mathematics

2 answers:

bija089 [108]2 years ago

7 0

The answer should be 50 the second option is the correct

USPshnik [31]2 years ago

6 0

The general form of a quadratic equation is that which is expressed in a form,
ax² + bx + c = 0
To write the equation in its general form, eliminate the decimal by multiplying the equation by 10. It now becomes,
3x² + 50x - 70 = 0
The value of b is therefore 50 and the answer is the second choice.

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I need help finding a measure

Sedbober [7]

Answer:

Which measure?

Step-by-step explanation:

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3 years ago

What's

Iteru [2.4K]

Answer:

374/105.

Step-by-step explanation:

1/3 of 8 * 2/7

= 1/3 * 8 * 2/7

= 8/3 * 2/7

= 16/21.

2/5 of 7

= 2/5 * 7

= 14/5.

Adding 16/21 + 14/5

= 80 / 105 + (14*21) / 105

= 80/105 + 294/105

= 374/105.

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2 years ago

a box contains 5 plain pencils and 3 pens. a second box contains 4 color pencils and 4 crayons. one item from each box is chosen

kodGreya [7K]

I think it would be 9 out of 16.

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2 years ago

What would the answer to the equation 3+6x=11-4y be

klemol [59]

   6x + 3 = -4y + 11
         - 3       - 3
         6x = -4y + 8
   6x + 4y = -4y + 4y + 8
   6x + 4y = 8
6x - 6x + 4y = -6x + 8
   4y = -6x + 8
      4    4
   y = -1¹/₂x + 2

6 0

2 years ago

A store sells Brazilian coffee for $10 per lb. and Columbian coffee for $14 per lb. If the store decides to make a 150-lb. blend

Artemon [7]

Answer:

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.

Step-by-step explanation:

Let "b" be the amount of Brazilian coffee, in pounds, required for the blend and "c" the amount of Colombian coffee required, in pounds.

Since there are two unknown variables a two-equation system is needed to solve the problem, we can set up one equation for weight and another for price as follows:

$b+c=150\\10*b+14*c=11*150$

Solve for "c" by multiplying the first equation by -10 and adding it to the second one:

$b+c=150\\10b+14c -10b-10c=11*150 -(10*150)\\4c=150\\c = 37.5$

Now, solve for b by replacing the value obtained into the first equation

$b+c=150\\b= 150 - 37.5\\b=112.5$

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.

6 0

2 years ago