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Amiraneli [1.4K]

3 years ago

7

Write the equation 0.3x 2 + 5x - 7 = 0 in general form and then choose the value of "b."

2 answers:

bija089 [108]3 years ago

7 0

The answer should be 50 the second option is the correct

USPshnik [31]3 years ago

6 0

The general form of a quadratic equation is that which is expressed in a form,
ax² + bx + c = 0
To write the equation in its general form, eliminate the decimal by multiplying the equation by 10. It now becomes,
3x² + 50x - 70 = 0
The value of b is therefore 50 and the answer is the second choice.

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What is the distance between (-7, -2) and (13,-23)

Zolol [24]

Step-by-step explanation:

here,

x1=-7

x2=13

y1=-2

y2=-23

so

$\boxed{\blue{ distance=\sqrt{(y2-y1)^2+(x2-x2)^2} }}$ ⠀

<em>=</em> $\tt{\sqrt{(-23-(-2))^2+(13-(-7))^2}}$ ⠀

= $\tt{\sqrt{(-21)^2+(20)^2} }$ ⠀

= $\tt{\sqrt{ 441+400} }$ ⠀

= $\tt{\sqrt{841} }$ ⠀

= $\tt{ 29 }$ ⠀

So,

the distance between (-7, -2) and (13,-23)=29

6 0

3 years ago

Which number line shows the solution of 5x - 25 < -15?

Anit [1.1K]

I think a. But I don’t understand this question.

8 0

3 years ago

The sum of Ellie’s ages an Genya’s age is 60. In 6 years, genus will be 8 times as old as Ellie. How old is Ellie now?

Aleonysh [2.5K]

Ellie's age = 58 years

Genya's age = 2 years

Step-by-step explanation:

Let e represent Ellie's age

and

g be Genya's Age

Then

$e+g = 60\ \ \ Eqn1$

In six years

Ellie will be e+6 years old and Genya will be g+6 years old

then

$g+6 = 8(e+6)\\g+6 = 8e+48\\g = 8e+48-6\\g = 8e+42\ \ \ Eqn2$

Putting g= 8e+42 in equation 1

$e+8e+42 = 60\\9e +42 -42 = 60-42\\9e = 18$

Dividing both sides by 9

$\frac{9e}{9} = \frac{18}{9}\\e=2$

Putting e = 2 in equation 1

$e+g = 60\\2+g = 60\\g = 60-2\\g = 58$

Hence,

Ellie's age = 58 years

Genya's age = 2 years

Keywords: Linear equations, variables

Learn more about linear equations at:

#LearnwithBrainly

7 0

3 years ago

$6,000 dollars is invested in two different accounts earning 3% and 5% interest. at the end of one year, the two accounts earned

Anettt [7]

<u>Answer-</u>

<em>$2000</em><em> were invested at 5%</em>

<u>Solution-</u>

Let x amount of money was invested at 5% and (6000-x) amount was invested as 3%

We know that,

$i=\dfrac{P\cdot r\cdot t}{100}$

Putting the values,

$i_1=\dfrac{P_1\cdot r_1\cdot t}{100}$

$i_1=\dfrac{x\cdot 5\cdot 1}{100}=\dfrac{5x}{100}$

And

$i_2=\dfrac{P_2\cdot r_2\cdot t}{100}$

$i_2=\dfrac{(6000-x)\cdot 3\cdot 1}{100}=\dfrac{3(6000-x)}{100}$

According to the question,

$\Rightarrow \dfrac{5x}{100}+\dfrac{3(6000-x)}{100}=220$

$\Rightarrow \dfrac{5x+3(6000-x)}{100}=220$

$\Rightarrow 5x+3(6000-x)=22000$

$\Rightarrow 5x+18000-3x=22000$

$\Rightarrow 5x-3x=22000-18000$

$\Rightarrow 2x=4000$

$\Rightarrow x=2000$

Therefore, $2000 were invested at 5%

8 0

4 years ago

Read 2 more answers

Choose the 2 correct statements from below.

Juliette [100K]

Answer:

Da

it maybe help u

please mark me as brainlist

7 0

4 years ago