Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Answer:
what is the question
Step-by-step explanation:
Answer:
37 units
Step-by-step explanation:
The two points form a right triangle so
a²+b²=c² so
(8-20)²(x values)+(40-5)²(y values)=c² (distance) so
12²+35²=c² so
144+1225=c²
1369=c²
c=37 units
Answer:
144 x 7 = 1008
The train can hold 1008 people
Mark brainlest
Step-by-step explanation:
