Ask question

Ask question

All categories

Vedmedyk [2.9K]

3 years ago

13

Alex bought 10 shares of Apex Co. for $95 each and later sold all of them at $105 each. This transaction resulted in what type o

f event?

2 answers:

katovenus [111]3 years ago

6 0

Answer:

capital gain Apex

Step-by-step explanation:

Sauron [17]3 years ago

4 0

If there are choices, please list them.

If not, it is certainly a capital gain if you live in the United States.

And capital gains are taxed. Again if you are in the US and you are not a trader, you will be taxed at a different higher rate if you sold it in less than a 1 year period.

Over a year and it is called a long term gain and the tax rate is lower. There's more about how to write off short term losses and gains, but that's getting into complexity you probably don't need to know about.

Answer: Capital Gain <<<<<<

You might be interested in

Which statements are true about the ordered pair (2, 3) and the system of equations?

vlabodo [156]

3x + 4y = 18......(2,3)
3(2) + 4(3) = 18
6 + 12 = 18
18 = 18...correct

2x - 2y = 2....(2,3)
2(2) - 2(3) = 2
4 - 6 = 2
-2 = 2...incorrect

when (2,3) is subbed into equation 1, it is true
when (2,3) is subbed into the second equation, it is false
the ordered pair (2,3) is not a solution to the system of linear equations

5 0

3 years ago

Read 2 more answers

Find all critical numbers of the function <img src="https://tex.z-dn.net/?f=g%28x%29%3Dx%5E%7B%5Cfrac%7B3%7D%7B4%7D%20%7D-2x%5E%

postnew [5]

Differentiate g using the power rule:

$g'(x) = \dfrac34 x^{\frac34-1} - 2\cdot\dfrac14 x^{\frac14-1}$

$g'(x) = \dfrac34 x^{-\frac14} - \dfrac12 x^{-\frac34}$

$g'(x) = \dfrac14 x^{-\frac34} \left(3 x^{\frac12} - 2\right)$

$g'(x) = \dfrac{3\sqrt x - 2}{4 x^{\frac34}}$

The critical points of g occur where g' is zero or undefined.

We have

$g'(x) = 0 \implies 3\sqrt x - 2 = 0 \implies \sqrt x = \dfrac23 \implies \boxed{x = \dfrac49}$

and the derivative is undefined for

$\dfrac1{g'(x)} = 0 \implies 4x^{\frac34} = 0 \implies \boxed{x=0}$

8 0

2 years ago

How long would it take for $45 to increase $150 at 6% compounded annually? (Answer to the nearest year.)

Svetach [21]

Answer:

It wil take approximately 20 years 7 months and 29 days for the account to go from $45 to $150, or 21 years rounded to the nearest year.

+ if this helped, please consider marking it the Brainliest

5 0

2 years ago

Can anyone help me out with this?

bogdanovich [222]

${\large{\textsf{\textbf{\underline{\underline{Question \: 1 :}}}}}}$

$\star\:{\underline{\underline{\sf{\purple{Solution:}}}}}$

$\bullet \sf \: {(a + b)}^{ab}$

<u>Putting value of a as 3 and b as -2, we get</u><u> </u><u>:</u>

$\longrightarrow \sf \: {( 3 + (- 2))}^{3 \times - 2}$

$\longrightarrow \sf \: {( 3 - 2)}^{3 \times - 2}$

$\longrightarrow \sf \: {( 1)}^{ - 6}$

• <u>Using negative Exponents Law</u>

$\longrightarrow \sf \dfrac{1}{ {1}^{6} }$

$\longrightarrow \sf \dfrac{1}{ 1 \times 1 \times 1 \times 1 \times 1 \times 1 }$

$\longrightarrow \sf \dfrac{1}{ 1 }$

$\longrightarrow \sf \purple{1}$

${\large{\textsf{\textbf{\underline{\underline{Question \: 2 :}}}}}}$

$\star\:{\underline{\underline{\sf{\red{Solution:}}}}}$

$\bullet \sf \: \dfrac{ {8}^{ - 1} \times {5}^{3} }{ {2}^{ - 4}}$

$\longrightarrow \sf \: {8}^{ - 1} \times {5}^{3} \times \dfrac{1}{{2}^{ - 4}}$

<u>• Using negative Exponents Law</u>

$\longrightarrow \sf \: {8}^{ - 1} \times {5}^{3} \times {2}^{4}$

$\longrightarrow \sf \: {8}^{ - 1} \times 5 \times 5 \times 5 \times {2}^{4}$

$\longrightarrow \sf \: {8}^{ - 1} \times 125 \times {2}^{4}$

$\longrightarrow \sf \: {8}^{ - 1} \times 125 \times 2 \times 2 \times 2 \times 2$

<u>• Using negative Exponents Law</u>

$\longrightarrow \sf \: \dfrac{1}{ \cancel{8}_{4}} \times 125 \times \cancel{2}_{1} \times 2 \times 2 \times 2$

$\longrightarrow \sf \: \dfrac{1}{ \cancel4_{2}} \times 125 \times \cancel{2}_{1} \times 2 \times 2$

$\longrightarrow \sf \: \dfrac{1}{ \cancel2} \times 125 \times \cancel{2} \times 2$

$\longrightarrow \sf \: 125 \times 2$

$\longrightarrow \sf \red{ 250}$

${\large{\textsf{\textbf{\underline{\underline{Question \: 3 :}}}}}}$

$\star\:{\underline{\underline{\sf{\green{Solution(1):}}}}}$

$\bullet \sf \dfrac{ \sqrt{32} + \sqrt{48} }{ \sqrt{8} + \sqrt{12} }$

$\longrightarrow \sf \dfrac{ \sqrt{4 \times 4 \times 2} + \sqrt{4 \times 4 \times 3} }{ \sqrt{2 \times 2 \times 2} + \sqrt{2 \times 2 \times 3} }$

$\longrightarrow \sf \dfrac{ \sqrt{ {4}^{2} \times 2} + \sqrt{ {4}^{2} \times 3} }{ \sqrt{ {2}^{2} \times 2} + \sqrt{ {2}^{2} \times 3} }$

$\longrightarrow \sf \dfrac{ 4\sqrt{ 2} + 4 \sqrt{ 3} }{ 2\sqrt{ 2} +2 \sqrt{ 3} }$

$\longrightarrow \sf \dfrac{ \cancel{ 4}_{2}(\sqrt{ 2} + \sqrt{ 3}) }{ \cancel{2}(\sqrt{ 2} + \sqrt{ 3}) }$

$\longrightarrow \sf \dfrac{ 2 \: \cancel{(\sqrt{ 2} + \sqrt{ 3}) } }{ \cancel{(\sqrt{ 2} + \sqrt{ 3})} }$

$\longrightarrow \sf \green{2}$

$\star\:{\underline{\underline{\sf{\blue{Solution(2):}}}}}$

$\bullet \sf \dfrac{ \sqrt{5} + \sqrt{3} }{ \sqrt{80} + \sqrt{48} - \sqrt{45} - \sqrt{27} }$

$\begin{gathered} \longrightarrow \sf \dfrac{ \sqrt{5} + \sqrt{3} }{ \sqrt{4 \times 4 \times 5} + \sqrt{4 \times 4 \times 3} - \sqrt{3 \times 3 \times 5} - \sqrt{3 \times 3 \times 3} } \end{gathered}$

$\begin{gathered}\longrightarrow \sf \dfrac{ \sqrt{5} + \sqrt{3} }{ \sqrt{ {4}^{2} \times 5} + \sqrt{ {4}^{2} \times 3} - \sqrt{ {3}^{2} \times 5} - \sqrt{ {3}^{2} \times 3} } \end{gathered}$

$\longrightarrow \sf \dfrac{ \sqrt{5} + \sqrt{3} }{4 \sqrt{ 5} + 4 \sqrt{ 3} - 3\sqrt{ 5} - 3\sqrt{ 3} }$

$\longrightarrow \sf \dfrac{ \sqrt{5} + \sqrt{3} }{4 \sqrt{ 5} - 3\sqrt{ 5} + 4 \sqrt{ 3} - 3\sqrt{ 3} }$

$\longrightarrow \sf \dfrac{ \cancel{ \sqrt{5} + \sqrt{3}} }{ \cancel{\sqrt{ 5} + \sqrt{ 3} } }$

$\longrightarrow \blue{1}$

${\large{\textsf{\textbf{\underline{\underline{Answers :}}}}}}$

• Question 1 - $\purple{1}$

• Question 2 - $\red{250}$

• Question 3(1) - $\green{2}$

• Question 3(2) - $\blue{1}$

${\large{\textsf{\textbf{\underline{\underline{ Concept \: :}}}}}}$

<u>★</u><u> </u><u>Negative</u><u> Exponents Law -</u>

$\bullet \sf \: {a}^{ - m} = \dfrac{1}{ {a}^{m} }$

★ $\sqrt{32}$ can be written as $4 \sqrt{2}$

‣ $\sqrt{48}$ can be written as $4 \sqrt{3}$

‣ $\sqrt{8}$ can be written as $2 \sqrt{2}$

‣ $\sqrt{12}$ can be written as $2 \sqrt{3}$

‣ $\sqrt{80}$ can be written as $4 \sqrt{5}$

‣ $\sqrt{48}$ can be written as $4 \sqrt{3}$

‣ $\sqrt{45}$ can be written as $3 \sqrt{5}$

‣ $\sqrt{27}$ can be written as $3 \sqrt{3}$

★ <u>During Addition and Subtraction</u>

• minus (-) minus (-) gives plus (+)

• minus (-) plus (+) gives minus (-)

• plus (+) minus (-) gives minus (-)

• plus (+) plus (+) gives plus (+)

• Also the sign of the resultant term depends upon the sign of the largest number.

${\large{\textsf{\textbf{\underline{\underline{ Note \: :}}}}}}$

• Swipe to see the full answer.

$\begin{gathered} {\underline{\rule{330pt}{3pt}}} \end{gathered}$

5 0

2 years ago

Becky lives 5 5\8 miles from school steve

andreev551 [17]

5 (5/8) * 1 (5/9) = 45/8 * 14/9 = 630/72 = 8 (54/72) = 8 (3/4) miles

4 0

2 years ago