Megan was employed by a large company. Her supervisor told her to falsify government reports. She refused and was fired. She sue
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Answer:
// here is code in c++.
#include <bits/stdc++.h>
using namespace std;
// recursive function to print digit of number in revers order
void rev_dig(int num)
{
if(num==0)
return;
else
{
cout<<num%10<<" ";
// recursive call
rev_dig(num/10);
}
}
// driver function
int main()
{
int num;
cout<<"enter a number:";
// read the number from user
cin>>num;
cout<<"digits in revers order: ";
// call the function with number parameter
rev_dig(num);
return 0;
}
Explanation:
Read the input from user and assign it to variable "num". Call the function "rev_dig" with "num" parameter.In this function it will find the last digit as num%10 and print it. Then call the function itself with "num/10". This will print the second last digit. Similarly it will print all the digits in revers order.
Output:
enter a number:1234
digits in revers order: 4 3 2 1
Diagram :
Answer:
Explanation:
The following is coded in Java. It asks the user for the number of inputs and then creates a loop to read all of the inputs and adds them to an ArrayList. Then it saves the last value in the array as the threshold. Finally, it loops through the array printing only the values less than or equal to the threshold. The program has been tested and the output can be seen in the image below.
import java.util.ArrayList;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
ArrayList<Integer> myList = new ArrayList<>();
System.out.println("How many inputs will you add? ");
int inputs = in.nextInt();
System.out.println("Enter inputs: ");
for (int i = 0; i< inputs; i++) {
int num = in.nextInt();
myList.add(num);
}
int threshold = myList.get(myList.size()-1);
System.out.println("Inputs Less than or Equal to Threshold: ");
for (int x: myList) {
if (x <= threshold) {
System.out.println(x);
}
}
}
}
