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4 years ago

What happens to the perimeter when the length of a rectangle is shortened?Please help!

1 answer:

3 0

The perimeter of a rectangle is just the sum of the lengths of its sides, so<span>taking half of each of the sides would make the total half of its original value also. </span>
Hope it helps.

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in a company 70% of the workers are women. if 1530 men work for the company how many workers are there in all? use pencil and pa

Ghella [55]

Women= 70%=?
Men= 100%-70%=30%=1,530
Women Workers= cross product (0.70*1,530)/0.3= 3,570
All workers= 1,530+3,570= 5,100

6 0

3 years ago

Read 2 more answers

The diameter of an average cell in a human body is 1 x 10^-5 mm. If the diameter of a pin head is 2 x 10^-2, how many body cells

Tatiana [17]

Answer:

2000

Step-by-step explanation:

diameter of an average cell= 1 x 10^-5 mm

diameter of a pin head= 2 x 10^-2

number of body cells that would fit on the pin head=2 x 10^-2 ÷ 1 x 10^-5

=2000 body cells

7 0

3 years ago

Rule and missing number what would it be

Maurinko [17]

The rule is: MULTIPLY BY 8 because it is true for every term

13 × 8 =104
22 × 8 = 176
44 × 8 = 352

So, 36 × 8 = 288

6 0

3 years ago

Read 2 more answers

The corner grocery store sells apples for $1.19 per pound. Which store sells apples at a lower unit price than the corner store

Valentin [98]

Answer:

B- 3.48 ÷ 3

Step-by-step explanation:

3.48 ÷ 3= 1.16

Hope this helps

-mercury

4 0

3 years ago

Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = x2 sin(z)i + y2j + xyk, S is the part of the paraboloid z = 9 − x2 −

Korolek [52]

The vector field

$\vec F(x,y,z)=x^2\sin z\,\vec\imath+y^2\,\vec\jmath+xy\,\vec k$

has curl

$\nabla\times\vec F(x,y,z)=x\,\vec\imath+(x^2\cos z-y)\,\vec\jmath$

Parameterize $S$ by

$\vec s(u,v)=x(u,v)\,\vec\imath+y(u,v)\,\vec\jmath+z(u,v)\,\vec k$

where

$\begin{cases}x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=(9-u^2)\end{cases}$

with $0\le u\le3$ and $0\le v\le2\pi$ .

Take the normal vector to $S$ to be

$\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k$

Then by Stokes' theorem we have

$\displaystyle\int_{\partial S}\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{2\pi}\int_0^3(\nabla\times\vec F)(\vec s(u,v))\cdot\left(\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^3u^3(2u\cos^3v\sin(u^2-9)+\cos^3v\sin v+2u\sin^3v+\cos v\sin^3v)\,\mathrm du\,\mathrm dv$

which has a value of 0, since each component integral is 0:

$\displaystyle\int_0^{2\pi}\cos^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\sin v\cos^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\sin^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\cos v\sin^3v\,\mathrm dv=0$

4 0

3 years ago