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Maurinko [17]
4 years ago
9

A painter has a 24 foot ladder that he is using to paint a house.for safety reasons the ladder must be placed at least 8 feet fr

om the base of the side of the house.To the nearest tenth of a foot how high can the ladder safely reach?
Mathematics
1 answer:
adoni [48]4 years ago
6 0

this is a pythagorean theorem problem. 24 is the whole ladder, and if you draw it out, is a hypotenuse. 8 is a leg.  a^2+ b^2 = c^2. so 8^2 + b^2 = 24^2

b^2 = 512, so b = sqrt(512) = 22.6

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45*0.4 = 18 square feet
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Find the area of each figure.
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An isosceles triangle has area of 105 ft2. If the base is 12 ft, what is the length of each leg? Round your answer to the neares
e-lub [12.9K]
Answer: Option D) 18.5 ft

Solution:
Area of the isosceles triangle: A=105 ft^2
Base of the isosceles triangle: B=12 ft
Length of each leg of the isosceles triangle: L=?

A=BH/2
Height of the isosceles triangle (perpendicular to the base): H=?

Replacing the known values in the formula of Area:
105 ft^2=(12 ft)H/2
105 ft^2=(6 ft)H

Solving for H: Dividing both sides by 6 ft:
(105 ft^2)/(6 ft)=(6 ft)H/(6 ft)
17.5 ft=H
H=17.5 ft

Using the Pytagoras Theorem:
c^2=a^2+b^2
with:
c=L=?
a=B/2=(12 ft)/2→a=6 ft
b=H→b=17.5 ft

L^2=(6 ft)^2+(17.5)^2
L^2=36 ft^2+306.25 ft^2
L^2=342.25 ft^2
sqrt(L^2)=sqrt(342.25 ft^2)
L=18.5 ft

Answer: The length of each leg is 18.5 ft
3 0
3 years ago
PLS AWNSER I WILL GIVE BRAILIEST
mash [69]

suzy will be walking around the circumfernnce of the fountain

circumfernce= 2\pi r

r is half of the diameter so it will be 5

2\pi (5)=31.4

as she walks around it 3 times it will be

31.4 *3 = 94.2 feet

so the answer is H. 94.2 feet

please mark as brainliest

3 0
3 years ago
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