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Shtirlitz [24]
3 years ago
12

This technique makes no a priori assumption of whether one variable is dependent on the other(s) and is not concerned with the r

elationship between variables; instead it gives an estimate on the degree of association between the variables:_________
a. Regression
b. Multiple regression
c. Means test
d. Correlation
Mathematics
1 answer:
Pepsi [2]3 years ago
8 0

Answer:

d. Correlation

Step-by-step explanation:

Based on the information being provided it can be said that this technique provides the correlation between two or more variables. Correlation explains any statistical relationship that exists between two different variables or sets of data, whether it is casual or not. Many times it is the degree to which a pair of variables are linearly related

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One half of your CDs are scratched. One fifth will not play properly. You have 40 CDs. How many will not work play properly
kvasek [131]
1/2 of 40= 20

40/5=8

20+8=28

28 of your CDs will not work properly.

I hope this helps!
6 0
3 years ago
Read 2 more answers
1. La suma de dos números es 115. El número mayor es dos veces más 22 unidades que el otro. Hallar
Lerok [7]

De acuerdo con un sistema de ecuaciones, tiene-se que los números son 31 y 84.

----------------

  • En el sistema de ecuaciones, tiene-se que los números son x e y.
  • Suma de 115, o sea, x + y = 115
  • <u>El número mayor es dos veces más 22 unidades que el otro</u>, o sea, x = 2y + 22

----------------

Primero se encuenta el número menor, <u>reemplazando la segunda ecuación en la primera:</u>

x + y = 115

2y + 22 + y = 115

3y = 93

y = \frac{93}{3}

y = 31

----------------

El número mayor es dado en <u>función de el menor</u>, o sea:

x = 2y + 22 = 2(31) + 22 = 62 + 22 = 84

Los números son 31 y 84.

Otro problema resuelto por sistema de ecuaciones es dado en brainly.com/question/24637096

6 0
3 years ago
How to solve this problem
finlep [7]

the answer  is 134 and the Remainder is 19

6 0
3 years ago
Merrill is playing a simple game of dice. For every 6 rolled, Merrill will win $5. For any other number, he must pay $2. How muc
Schach [20]

Solution -

The probability of getting 6 from a single roll of a fair dice = \frac{1}{6}

The probability of getting any other number rather than 6 would be 1-\frac{1}{6} = \frac{5}{6}

So when the outcome is 6, then he wins $5 ,otherwise he has to pay $2

So

E(X) = Expectation value = (\frac{1}{6} )(5) - (\frac{5}{6} )(2)                                    ( ∵ $5 gain so +ve and $2 loss so -ve)

=\frac{-5}{6}

∴ So Merrill will lose \frac{5}{6} dollar


7 0
3 years ago
Read 2 more answers
A card is drawn from a standard deck of 5252 playing cards. What is the probability that the card will be a heart or a face card
mr_godi [17]

Answer:

The probability that the card will be a heart or a face card is P=0.4231.

Step-by-step explanation:

We have a standard deck of 52 cards.

In this deck, we have 13 cards that are a heart.

We also have a total of 12 face cards (4 per each suit). So there are 3 face cards that are also a heart.

To calculate the probability that a card be a heart or a face card, we sum the probability of a card being a heart and the probability of it being a face card, and substract the probability of being a heart AND a face card.

We can express that as:

P(H\,or\,F)=P(H)+P(F)-P(H\&F)\\\\P(H\,or\,F)=13/52+12/52-3/52=22/52=0.4231

4 0
3 years ago
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