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PSYCHO15rus [73]
3 years ago
10

What are the terms in the expression 350n-30n+350-(50+10n)

Mathematics
1 answer:
trapecia [35]3 years ago
5 0
Terms- 350n, 30n, 350, and (50+10n) (four terms)
coefficients- 350,30,and 10
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7<br><img src="https://tex.z-dn.net/?f=7%20%20%5E%7B2%7D%20-%20%20%7C6%20-%202%287%29%7C%20%5Ctimes%203%20%5E%7B2%7D%20" id="Tex
frutty [35]

Answer:

-23

Step-by-step explanation:

you calculate 49-|6-14|x 9

you then calculate the absolute value

49-|-8|x 9

then multiply the numbers

49-8 x 9

calculate those numbers

49 - 72

your solution will be -23

5 0
3 years ago
20 POINTS TO ANYONE! HURRYYYY HURRY HURRY
Oksi-84 [34.3K]

Answer:

a

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Idk sooo please help
borishaifa [10]

Answer:

20 points

Step-by-step explanation:

Points:

  • 21, 13, 14 and x for the last game

Average:

  • (21+13+14+x) / 4 = 17
  • 48 + x = 4*17
  • 48 + x = 68
  • x = 68 - 48
  • x = 20

They must score 20 points

6 0
3 years ago
George and Paula are running around a circular track. George starts at the westernmost point of the track, and Paula starts at t
arsen [322]

Answer:

George is 43.20 ft East of his starting point.

Step-by-step explanation:

Let Paula's speed be x ft/s

George's speed = 9 ft/s

Note that speed = (distance)/(time)

Distance = (speed) × (time)

George takes 50 s to run a lap of the track at a speed of y ft/s

Meaning that the length of the circular track = y × 50 = 50y ft

George and Paula meet 14 seconds after the start of the run.

Distance covered by George in 14 seconds = 9 × 14 = 126 ft

Distance covered by Paula in 14 seconds = y × 14 = 14y ft

But the sum of the distance covered by both runners in the 14 s before they first meet each other is equal to the length of the circular track

That is,

126 + 14y = 50y

50y - 14y = 126

36y = 126

y = (126/36) = 3.5 ft/s.

Hence, Paula's speed = 3.5 ft/s

Length of the circular track = 50y = 50 × 3.5 = 175 ft

So, in 4 minutes (240 s), with George running at 9 ft/s, he would have ran a total distance of

9 × 240 = 2160 ft.

2160 ft around a circular track of length 175 ft, means that George would have ran a total number of laps (2160/175) = 12.343 laps.

Breaking this into 12 laps and 0.343 of a lap from the starting point. 0.343 of a lap = 0.343 × 175 = 60 ft

So, 60 ft along a circular track subtends an angle θ at the centre of the circle.

Length of an arc = (θ/360°) × 2πr

2πr = total length of the circular track = 175

r = (175/2π) = 27.85 ft

Length of an arc = (θ/360) × 2πr

60 = (θ/360°) × 175

(θ/360°) = (60/175) = 0.343

θ = 0.343 × 360° = 123.45°

The image of this incomplete lap is shown in the attached image,

The distance of George from his starting point along the centre of the circular track = (r + a)

But, a can be obtained using trigonometric relations.

Cos 56.55° = (a/r) = (a/27.85)

a = 27.85 cos 56.55° = 15.35 ft

r + a = 27.85 + 15.35 = 43.20 ft.

Hence, George is 43.20 ft East of his starting point.

Hope this Helps!!!

6 0
3 years ago
In one day Sasha got 1 hour of sleep for every 3 hours she was awake if there are 24 hours in a day how many hours of sleep did
Gre4nikov [31]

Answer:

Hours slept = 6 hours

Hours awake = 18 hours

Step-by-step explanation:

Sasha got 1 hour of sleep for every 3 hours she was awake.

So,

<u>This means:</u>

Slept : Awake = 1 : 3

Total hours in a day = 24 hours

<u>Let </u>

Hours slept = 1x and hours awake = 3x

<u>Hence,</u>

1x + 3x = 24 hours

4x = 24

Divide both sides by 4

x = 24 / 4

x = 6

<u>So,</u>

Hours slept = 1(6) = 6 hours

Hours awake = 3(6) = 18 hours

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
2 years ago
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