What are the terms in the expression 350n-30n+350-(50+10n)

A holiday costs £1900. Work out the<br> price after a 9% discount.

Svetradugi [14.3K]

Answer:

$1729

Step-by-step explanation:

$\frac{100-9}{100} * 1900$

7 0

3 years ago

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Maria in on the school softball team. Her team has won 3 out of 12 games. She is having an excellent season hitting the softball

GarryVolchara [31]

Ignore the part about her batting attempts, it is extra. Her winning ratio is 3/12 which is 1/4 simplified and if you do 1/4 or 3/12 you get 0.25 which is the decimal of how many games she won / how many total. To convert 0.25 to percentage multiply it by 100 to get 25% D

5 0

3 years ago

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Line ℓ1 has the equation

aleksley [76]

Answer:

$\sqrt{2}$ units

Step-by-step explanation:

The Line 1 has equation x + y = 5 ....... (1) , and

Line 2 has equation x + y = 3 .......... (2)

Now, we have to find the perpendicular distance between line 1 and line 2.

We can say that (3,0) is a point on line 2 as it satisfies the equation (2).

Now, the perpendicular distance from point (3,0) to the line 1 will be given by the formula

$\frac{|3 + 0 - 5|}{\sqrt{1^{2}+ 1^{2}}} = \frac{2}{\sqrt{2}} = \sqrt{2}$ units (Answer)

We know that the perpendicular distance from any external point ( $x_{1},y_{1}$ ) to a given straight line ax + by + c = 0 is given by the formula $\frac{|ax_{1} + by_{1} + c|}{\sqrt{a^{2} + b^{2}}}$ .

3 0

3 years ago

Help! I will give brainliest, amazing rating, and thanks for answer!

prisoha [69]

First, let’s begin with part A of the question. To find the mean, we must find the average of Rolinda’s test scores by adding them all together and then dividing the sum by 5 (the number of test scores). This is shown below:

(85 + 85 + 60 + 62 + 59) / 5

351/5

70.2

Therefore, the mean of Rolinda’s test scores is 70.2.

Next, we should find the median, or the middle number of the sequence after we order the numbers from smallest to largest. This is shown below:

59, 60, 62, 85, 85

Since 62 is the middlemost number in the list, the median is 62.

Finally, we must find the mode, or the most common number in the list. Since 85 is the only number that occurs more than once, we know that the mode is 85.

Next, we move on to Part B. The measure that supports Rolinda’s claim that she is doing well in her Spanish class is the mode, because it is the highest measure out of the three.

The answer to Part C is as follows: This is misleading because the mode is not an accurate representation of all of Rolinda’s test scores and the range that they cover, it only represents Rolinda’s highest score, which she happened to score twice.

Hope this helps!

4 0

4 years ago

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use the information provided to write the standard form equation of each hyperbola vertices:(4,14), (4,-10) foci: (4,15), (4,-11

Evgen [1.6K]

So... if you notice the picture below, based on the given vertices, is a hyperbola with a vertical traverse axis

meaning for the equation, the fraction with the "y" variable is the positive fraction, thus $\bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1$

so... what' the point h,k for the center? well, just take a peek at the graph, the center is half-way between both vertices, that's h,k

what's the "a" component or the traverse axis... well, is the distance from one vertex to the center, notice the picture, notice how many units from either vertex to the center, that's "a"

now.. what's "b"? well, "b" comes from the conjugate axis, or the other runnning over the x-axis hmm the smaller one in this case.... well, we dunno what "b" is

however, we know the distance from either focus, to the center of the hyperbola, and that distance "c", is $\bf c=\sqrt{a^2+b^2}$

notice the picture, notice the distance from either focus to the center, that's the distance "c", thus $\bf c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b$

that'd be "b"

bearing in mind that $\bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center= ({{ h}},{{ k}})\\\\ b=\sqrt{c^2-a^2}
\end{cases}$

8 0

4 years ago