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3 years ago

I need help with the answer i also need to explain this question

Mathematics

2 answers:

finlep [7]3 years ago

6 0

Answer:

B) 20

Step-by-step explanation:

telo118 [61]3 years ago

4 0

Answer: B: 20

Step-by-step explanation: We can take 40% as a fraction to make it 4/10, simplifying gives 2/5. 2/5 of 50 is 20!

Hope this Helps!

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M-5=49 please answer I need help

torisob [31]

M = 54 bro bro bro give me BRANLIEST

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3 years ago

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Pleas help, I’ll mark as brainliest.

STatiana [176]

Answer:

Step-by-step explanation:

f(4) = -1

g(4) = -2

(f + g)(4) = f(4) + g(4) = -3

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3 years ago

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What is the approximate distance between the points (–5, 4) and (2, –8)?

Volgvan

Answer:

option d is the correct answer

Step-by-step explanation:

Distance Equation Solution:

d=radical(2−(−5))2+(−8−4)2

d=radical(7)2+(−12)2

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3 years ago

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urn I contains 1 red chip and 2 white chips; urn II contains 2 red chipsand 1 white chip. One chip is drawn at random from urn I

vitfil [10]

Answer:

Following are the answer to this question:

Step-by-step explanation:

In the question first calls the W if the transmitted chip was white so, the W' transmitted the chip is red or R if the red chip is picked by the urn II.

whenever a red chip is chosen from urn II, then the probability to transmitters the chip in white is:

$P(\frac{w}{R}) = \frac{P(W\cap R)}{P(R)} \ \ \ \ \ _{Where}\\\\P(R) = P(W\cap R) + P(W'\cap R) \\$

The probability that only the transmitted chip is white is therefore $P(W) = \frac{2}{3}\\$ , since urn, I comprise 3 chips and 2 chips are white.

But if the chip is white so, it is possible that urn II has 4 chips and 2 of them will be red since urn II and 2 are now visible, and it is possible to be: $P(\frac{R}{W}) = \frac{2}{3}$

$P(W\cap R) = P(W) \times P(\frac{R}{W}) \\$

$= \frac{2}{3}\times \frac{2}{4} \\\\= \frac{2}{3}\times \frac{1}{2} \\\\= \frac{2}{3}\times \frac{1}{1} \\\\=\frac{1}{3}\\\\= 0.333$

Likewise, the chip transmitted is presumably red $(P(W')= \frac{1}{3})$ and the chip transferred is a red chip of urn II $(P(\frac{R}{W'})= \frac{3}{4}$ , and a red chip is likely to be red $(\frac{R}{W'})$ .