A. Alright, we want to multiply one equation by a constant to make it cancel out with the second. Since the first equation has a "blank" y, let's multiply the first equation by <em>2</em>.
3x-y=0 → 2(3x-y=0) = 6x - 2y = 0
5x+2y=22
The answer for this part would be: 6x - 2y = 0 and 5x + 2y = 22
B. So now we combine them:
6x - 2y = 0
+ + +
5x + 2y = 22
= = =
11x + 0 = 22 ← The answer
C. Now that we have the equation 11x = 22, we solve for x
11x = 22 ← Divide both sides by 11
x = 2 ← The answer
D. Now that we have x=2, we plug that back in to 5x+2y=22 and solve for y:
5(2)+2y = 22
10 + 2y = 22
2y = 12
y = 6
<u>Therefore, the solution to this problem is x = 2 and y = 6</u>
Answer:
The correct answer is 10+6p
Step-by-step explanation:
The mistake is that for the first step instead of distributing 2 to 3p and 1 they added 8+2 first. your actually supposed to distribute and get, 8+6p+2, then combine like terms and get 10+6p
Answer:
-18
Step-by-step explanation:
Left Hand Side = -2(7a + 9b) = -14a - 18b
Comparing it with Right Hand Side, ? = -18
Answer:
20 slices
Step-by-step explanation:
