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raketka [301]
3 years ago
15

A town has three roads that form an obtuse triangle. James wants to set up a refreshment stand so that the shortest distance fro

m his stand to each road is the same for all three roads. Where should he set up the refreshment stand?
A. on the centroid
B. on the circimcenter
C. on the incenter
D. on the median

I have an hour 50min to do this please help!
Mathematics
1 answer:
GarryVolchara [31]3 years ago
4 0
He should set up the refreshment stand on the incenter of the obtuse triangle. The incenter of a triangle is described as the intersection between the angle bisectors of a triangle. The inradius are the line segments from the incenter of the triangle to each of the three sides of the triangle which are all equal. The inradius is depicted as the radius of an inscribed circle in the triangle. Therefore, the shortest equal distance from his stand to each road is C. on the incenter.
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What is 25% of 75? <br><br> Answer now! High value question on the market!<br><br> [ Really! ]
coldgirl [10]

Step-by-step explanation:

p\%=\dfrac{p}{100}\\\\25\%=\dfrac{25}{100}=0.25\\\\25\%\ of\ 75\to 0.25(75)=18.75

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Read 2 more answers
Help please thank you!!!!
Nana76 [90]
1. You have that:

 - The trapezoids are similar.
 - The larger  base of the smaller trapezoid is 18 m and its area is 310 m².
 - The larger base of the larger trapezoid is 32 m.

 2. Then:

 Sides=18/32
 Sides=9/16

 Area=(9/16)²
 Area=81/256

 3. Now, you can find the area of the larger trapezoid, as below:

 81/256=310/x
 81x=(310)(256)
 x=79360/81
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 Therefore, the answer is: The area of the larger trapezoid is 980 m².
4 0
3 years ago
Two dice are numbered 1,2,3,4,5,6 and 1,1,2,2,3,3 respectively. They are rolled and
Alexxx [7]

Answer:

P(2) = 1/18

P(3) = 1/9

P(4) = 1/6

P(5) = 1/6

P(6) = 1/6

P(7) = 1/6

P(8) = 1/9

P(9) = 1/18

Step-by-step explanation:

Each die has six possible outcomes, so both dice together have 6*6 = 36 outcomes:

(1,1), (1,1), (1,2), (1,2), (1,3), (1,3),

(2,1), (2,1), (2,2), (2,2), (2,3), (2,3),

(3,1), (3,1), (3,2), (3,2), (3,3), (3,3),

(4,1), (4,1), (4,2), (4,2), (4,3), (4,3),

(5,1), (5,1), (5,2), (5,2), (5,3), (5,3),

(6,1), (6,1), (6,2), (6,2), (6,3), (6,3).

The sum of the values for each outcome is:

2, 2, 3, 3, 4, 4,

3, 3, 4, 4, 5, 5,

4, 4, 5, 5, 6, 6,

5, 5, 6, 6, 7, 7,

6, 6, 7, 7, 8, 8,

7, 7, 8, 8, 9, 9.

To find the probability of each sum, we just need to divide the number of times this sum appears over the total number of possibilities (36), so we have:

P(2) = 2/36 = 1/18

P(3) = 4/36 = 1/9

P(4) = 6/36 = 1/6

P(5) = 6/36 = 1/6

P(6) = 6/36 = 1/6

P(7) = 6/36 = 1/6

P(8) = 4/36 = 1/9

P(9) = 2/36 = 1/18

8 0
3 years ago
Simplify 5+10−2^3 <br> thanks in advance
andrey2020 [161]
5+10-2^3
= 7

Step by step:
5+10-2^3
= 15 - 2^3
= 15 - 8
= 7
8 0
3 years ago
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