All categories

4 years ago

How many glucose molecules are made during one cycle of photosynthesis?

1 answer:

5 0

In the calvin cycle, glyceraldehyde-3-phosphate (G3P) is first and foremost responsible for making glucose. To make one G3P molecule, you need three turns of the calvin cycle. In the GP3 molecule, you hade 3 fixed carbon atoms. So to make a six-carbon glucose molecule, you need two GP3 molecules. Therefore it takes 6 turns of the calvin cycle (photosynthesis) to make a glucose molecule.

You might be interested in

PLEASE HELP ME!!! 30 points (also marked Brainlest)

erica [24]

Answer:

Explanation:

2-They live in burrows that they dig into the soil. This helps

aerate the soil and improve plant growth.

Crab feeding and burrowing mixes nutrients into the soil,

which is also good for plants. (important)

Fiddler crabs also promote marsh

plant growth that is important for the protection of coastal

cities from hurricanes.

7 0

3 years ago

PLEASE HELP THIS IS MY LAST QUESTION

Nat2105 [25]

Answer:

dissolve wastes and nutrients

Explanation:

Water is a bipolar solvent. the polar arrangement of oxygen and hydrogen atoms allows water to have a positive electrical charge and a negative charge. This allows the water molecule to become attracted to many different types of molecules. Through this attraction, water can become so heavily attracted to disrupt the attractive forces that hold the compounds and, thus, dissolving them.

7 0

3 years ago

Type of energy source that's will eventually be used up

vladimir1956 [14]

The answers is fossil fuels.

4 0

3 years ago

Which snack is the healthiest option for jun based on the data in the table

baherus [9]

What table is it for the question there is no data or table

8 0

3 years ago

Alu element at the PV92 locus on Chromosome 16. In this population, 436 people have a heterozygous genotype and 102 people have

Lesechka [4]

Answer:

Explanation:

According to the exercise we can infer that for the Alu insert:

p: positive allelic frequency

q: negative allelic frequency

maintaining that the population is in equilibrium we can carry out the following formula

p + q = 1 and pp + 2pq + qq = 1

looking for the genotype frequency we clear and obtain the following data

genotype frequency of 2pq = 436/1000 = 0.436

The genotype frequency of qq = 102/1000 = 0.102

This is how we look now:

number of positive people for Alu = 1000- (436 + 102) = 1000- 538 = 46

In this way it is resolved that:

genotypic frequency of pp = 462/1000 = 0.462

p = 0.462 + (0.436 / 2) = 0.462 + 0.218 = 0.680

q = 0.102+ (0.436 / 2) = 0.102 + 0.218 = 0.320

According to the exercise carried out it is deduced:

The value of p in the population is = 0.68

We conclude that our prognosis showing a homozygous positive genotype is: 0.462

6 0

3 years ago