The probability distribution for a random variable x is given in the table X: -5,-3,-2,0,2,3 Probability: .17,.13,.33,.16,.11,.1
Ivan
Answer:
0.6 probability that 
Step-by-step explanation:
The probability distribution is given in the table.
Probability that x is between -2 and 2.
Between -2 and 2, inclusive, we have -2, 0 and 2. So

From the table:
. So

0.6 probability that 
Answer:
dsgberhyujxgkloyjnhbgfvbhnjklkjhbgfdfghjkiopolkjhgfew
Step-by-step explanation:
Answer:
Interval [16.34 , 21.43]
Step-by-step explanation:
First step. <u>Calculate the mean</u>

Second step. <u>Calculate the standard deviation</u>



As the number of data is less than 30, we must use the t-table to find the interval of confidence.
We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).
We must then choose t = 1.476 (see attachment)
Now, we use the formula that gives us the end points of the required interval

where n is the number of observations.
The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43
Answer:
61
Step-by-step explanation:
If you want only the middle number, then call it x
the largest of the 3 is x + 1
The smallest of the 3 is x - 1
Add
x + 1 + x - 1 + x = 183 Cancel the 1s out.
x + x + x = 183 Combine the like terms on the left
3x = 183 Divide by 3
x = 183/3 Do the division
x = 61
The middle number is 61
Answer:
a=-36
Step-by-step explanation:
1/6(a+12)=-4
1) Distribute <u>1/6</u> to a and 12:
1/6a+2=-4
2) Subtract 2 from both sides:
1/6a=-6
3) Multiply both sides by the reciprocal of 1/6: (6/1)
a=-36
Let me know if you have any confusion on how I reached the solution :)